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3 years ago

Solve for slope. (-2,7) (-1,6)

Mathematics

2 answers:

Lostsunrise [7]3 years ago

7 0

Answer:

m = - 1/3

Thats the answer.

Step-by-step explanation:

Ede4ka [16]3 years ago

4 0

The answer is m=-1 if you use the slope formula you come up with only that answer if you just wanna find the slope of the two coordinates.

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A mixture of pulverized fuel ash and Portland cement to be used for grouting should have a compression strength of more than 130

nekit [7.7K]

Answer:

The null hypothesis is: u >= 1300 KN/m^2

And the alternative hypothesis is:

u < 1300 KN/m^2.

Step-by-step explanation:

The null hypothesis describes hat there is no difference or assiciation between variables of a specific population or that it is a particular average value while the alternative hypothesis states otherwise.

In this case study, the null hypothesis is: u >= 1300 KN/m^2

And the alternative hypothesis is:

u < 1300 KN/m^2.

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3 years ago

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neonofarm [45]

Answer:

ur dumb kid

Step-by-step explanation

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3 years ago

Make a frequency table to show the following test times (in minutes) for a reading test. 81, 63, 61, 58, 72, 70, 79, 68, 82, 64,

kodGreya [7K]

Sorry about my handwriting. this is what your graph should look like

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4 years ago

The double number line shows that it takes 444 hours for Karin to fold 282828 paper cranes.

Zanzabum

Answer:

Karin can fold 7, 14 and 21 paper cranes in 1, 2 and 3 hours respectively.

Step-by-step explanation:

Please kindly see the attached for explanation.

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3 years ago

Read 2 more answers

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .

Observe the image below.

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4 years ago