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3 years ago

Example of non-statistical question , statistical question

1 answer:

4 0

Answer: A non-statistical For example, the question, 'What is 2 plus 2?' is a non-statistical question. This question has only one correct answer that doesn't change

A statistical question For example, there will likely be variability in the data collected to answer the question, "How much do the animals at Fancy Farm weigh?"

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Assume that the number of messages input to a communication channel in an Exponential distribution with 7 messages arriving in a

NARA [144]

The probability that more than 3 messages will arrive during a 30-second interval is $P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}$ .

According to the statement

we have given that the an Exponential distribution with 7 messages arriving in a 10 second period and we have to find the probability that more than 3 messages will arrive during a 30-second interval.

So, For this purpose, we know that the

The probability is the measure of the likelihood of an event to happen. It measures the certainty of the event.

And the given information is that :

3 messages will arrive during a 30-second interval.

Then

Probability = P(X=1) + P(X=2) + P(X=3).Then

The probability become according to the exponential distribution:

$P(X=1)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\\P(X=2)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\\P(X=3)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\$

And then substitute the values in it then

$Probability = \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^1}{1!}\ +\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^2}{2!}\ + \dfrac{e^{-0.3 \times 20} (0.3 \times 20)^3}{3!}\\$

This is the probability.

So, The probability that more than 3 messages will arrive during a 30-second interval is $P(X=n)=\dfrac{e^{-0.3 \times 20} (0.3 \times 20)^n}{n!}$ .

Learn more about probability here

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7 0

2 years ago

What is the following sum 4(^5√x^2y)+3(^5√x^2y)

satela [25.4K]

I think it should be B but I’m probably wrong so risk it if you want sorry

8 0

3 years ago

Read 2 more answers

An object is launched upward at 64 ft/sec from a platform that is 80 feet high. What is the objects maximum height if the equati

Free_Kalibri [48]

Max height is the vertex
convert to vertex form (y=a(x-h)^2+k) by completeing the square

h(t)=-16(t²-4t)+80
h(t)=-16(t²-4t+4-4)+80
h(t)=-16((t-2)²-4)+80
h(t)=-16(t-2)²+64+80
h(t)=-16(t-2)²+144

vertex is (2,144)
at t=2, the height is 144

max height is 144ft

4 0

3 years ago

How do you solve 34.86 x 1.2?

Nezavi [6.7K]

Answer: 41.832

Step-by-step explanation:

I like to write decimals without decimals when multiplying. for this I would do

3486 x 12 which equals 41832 then You would move the decimal up from 3 spaces from the 2 from 41832 which would put the decimal between the 1 and 8

3 0

3 years ago

The volume of a cube is 27 cubic inches. What is the length of one edge of the cube?

hjlf

The volume for any cube is length x width x height,
so in this case because all side of cube is the same, let it be y.
y x y x y = 27
y = 3
so each side will be 3 inches

3 0

3 years ago