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sineoko [7]
3 years ago
14

Name a common product that contains a base

Biology
1 answer:
frez [133]3 years ago
5 0
Ammonia, drain cleaner, baking soda, chalk, toothpaste, Windex, bleach, laundry detergent, shampoo, and egg whites (household base)
I hope this helps if not I’m sorry
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Anjuli performed an experiment to determine the respiration rate of yeast. She determined this by measuring the amount of carbon
DanielleElmas [232]
<span>She was measuring a rate of change is probably the correct answer once the graph is not shown.

A rate of change in this case would refer to </span><span>the speed at which the respiration</span> is happening<span> over the measured period of time. G</span>raphically, is the slope of a line and that is why is easier to gather conclusions from a line graph instead of any other type.<span>
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5 0
4 years ago
Read 2 more answers
If ADP stands for adenosine
katrin2010 [14]

Answer:

b) 2

Explanation:

di means two

3 0
3 years ago
What are two ways that crossing over contributes to genetic variation​
Lisa [10]
Crossing over, or recombination, is the exchange of chromosome segments between nonsister chromatids in meiosis. Crossing over creates new combinations of genes in the gametes that are not found in either parent, contributing to genetic diversity.
6 0
4 years ago
A performer, seated on a trapeze, is swinging back and forth with a period of 8.90 s. If she stands up, thus raising the center
iren2701 [21]

Answer:

8.800s

Explanation:

When the performer swings, she oscillates in SHM about Lo of the string with time period To = 8.90s.

First, determine the original length Lo, where for a SHM the time period is related to length and the gravitational acceleration by the equation

T = 2π×√(Lo/g)..... (1)

Let's make Lo the subject of the formulae

Lo = gTo^2/4π^2 ..... (2)

Let's put our values into equation (2) to get Lo

Lo = gTo^2/4π^2

= (9.8m/s^2)(8.90s)^2

------------------------------

4π^2

= 19.663m

Second instant, when she rise by 44.0cm, so the length Lo will be reduced by 44.0cm and the final length will be

L = Lo - (0.44m)

= 19.663m - 0.44m

= 19.223m

Now let use the value of L into equation (1) to get the period T after raising

T = 2π×√(L/g)

= 2π×√(19.223m/9.8m/s^2)

= 8.800s

7 0
3 years ago
9. Which is the pathway of oxygen from lungs into the body tissues?
Setler [38]

Answer:

The pathway of oxygen from lungs to the body tissues is alveoli → red blood cells → blood vessels → tissues (option b).

Explanation:

The oxygen (O₂) required by the tissues comes from the air inspired by the respiratory system. The pathway of entry of O₂ to the body and tissues is:

  1. O₂ from the air reaches the lungs.
  2. In the pulmonary alveoli, gas exchange occurs, that is, O₂ passes into the blood capillaries and is captured by the red blood cells, while CO₂ is released and passes into the alveoli to be eliminated.
  3. O₂ in the red blood cells travels through the blood vessels.
  4. The tissues receive the O₂ and a second gaseous exchange occurs at the tissue level, as they release CO₂ that will be carried to the alveoli.

Tissue oxygenation depends on the integrity of the respiratory and circulatory systems.

<em>     The other options do not show the correct order in which the oxygen travels from the alveoli to the tissues.</em>

8 0
4 years ago
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