In the reaction, 2Na (s) + 2H2O (l) → 2NaOH (aq) + H2 (g), which of the reactants or products is in the gas phase?
1 answer:
Clearly H2 is in gaseous state as could be seen from (g) written with it which tells state of the product
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Si -Atomic number -14 -1s2 2s2 2p6 3s2 3p2 - 4 valence electrons
You would add water to the mixture to dissolve the salt. When the salt is dissolved, you have your sand alone.
Answer:
K = 0.0003 s⁻¹
Explanation:
The reaction is
2N₂O₅ = 4NO₂ + O₂
The equilibrium is
![K[N_{2} O_{5} ]=-\frac{1}{2} \frac{d[N_{2} O_{5} ]}{dt} \\\int\limits^y_x {d[N_{2} O_{5} ]}{} \, =-2k\int\limits^t_0 {dt} \,\\ln[N_{2} O_{5} ]=-2kt+ln[N_{2} O_{5} ]](https://tex.z-dn.net/?f=K%5BN_%7B2%7D%20O_%7B5%7D%20%5D%3D-%5Cfrac%7B1%7D%7B2%7D%20%5Cfrac%7Bd%5BN_%7B2%7D%20O_%7B5%7D%20%5D%7D%7Bdt%7D%20%5C%5C%5Cint%5Climits%5Ey_x%20%7Bd%5BN_%7B2%7D%20O_%7B5%7D%20%5D%7D%7B%7D%20%5C%2C%20%3D-2k%5Cint%5Climits%5Et_0%20%7Bdt%7D%20%5C%2C%5C%5Cln%5BN_%7B2%7D%20O_%7B5%7D%20%5D%3D-2kt%2Bln%5BN_%7B2%7D%20O_%7B5%7D%20%5D)
a plot is attached
From the plot, the slope is -0.0006
-2 * K = -0.0006
K = 0.0003 s⁻¹