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hichkok12 [17]
4 years ago
10

The logistic growth function at right describes the number of​ people, ​f(t)​, who have become ill with influenza (t) weeks afte

r its initial outbreak in a particular community.
f (t) = 200,000/1+2000e^-t
a. How many people became ill with the flu when the epidemic​ began?
b. How many people were ill by the end of the fourth​ week?
c. What is the limiting size of the population that becomes​ ill?
Mathematics
1 answer:
Taya2010 [7]4 years ago
4 0

Answer:

Given function is:

f(t)=\frac{200000}{1+2000e^{-t}}

Part A:

When t = 0

f(0)=\frac{200000}{1+2000e^{-0}}

= \frac{200000}{1+2000e^{-0}}

= \frac{200000}{1+2000}

=  \frac{200000}{2001}

= 99.95 rounding to 100 people.

Part B:

f(4)=\frac{200000}{1+2000e^{-4}}

= \frac{200000}{1+2000(0.0183156)}

= \frac{200000}{1+36.6312}

= \frac{200000}{37.6312}

= 5314.73

So, approximately 5,315 people were ill by the end of the 4th week.

Part C:

Let 't' be approaching infinity.

e^{-t} will approach zero, so f(infinity)=\frac{200000}{1+0}

f(infinity)=200000

Hence, the limit is that all of the persons can become ill.

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