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Serga [27]
2 years ago
12

What is the solution to the proportion x\45 = 8/18 a.x =16 b.x =20 c.x =35 d.x =101.25

Mathematics
1 answer:
exis [7]2 years ago
5 0
<span>Give the solution proportion of the given number
=> x : 45 = 8 : 18
=> Let’s start solving the proportion
=> 45 * 8 = 360
=> 360 / 18 =20
Thus the answer is letter B. X = 20
let’s check if we have correct answer
=> 20 * 18 = 360
=> 360 / 45 = 8
=> 20 * 18 = 360
=> 360 / 8 = 45
Thus, we have the same answer.
 

</span>



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Find the sum of the angle measures in the figure below​
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6 0
3 years ago
The given measurements may or may not determine a triangle. If not, then state that no triangle is formed. If a triangle is form
Fofino [41]
<h3>Answer:</h3><h3>C = 28.2, A = 25.8, a = 6.5</h3>

See diagram below.

==============================================

Work Shown:

Given info is

B = 126 degrees

b = 12

c = 7

Use the Law of Sines to solve for angle C

sin(C)/c = sin(B)/b

sin(C)/7 = sin(126)/12

sin(C)/7 = 0.067418082864579

sin(C) = 7*0.067418082864579

sin(C) = 0.471926580052053

C = arcsin(0.471926580052053) or C = 180-arcsin(0.471926580052053)

C = 28.1594278560921 or C = 180-28.1594278560921

C = 28.1594278560921 or C = 151.840572143908

C = 28.2 or C = 151.8

We have two possible angle values for C.

-----------------

If C = 28.2, then A = 180-B-C = 180-126-28.2 = 25.8

If C = 151.8, then A = 180-B-C = 180-126-151.8 = -97.8

So it is not possible for C = 151.8 (because it leads to angle A being negative)

Therefore, only C = 28.2 is possible.

-----------------

Use the law of cosines to find the remaining side 'a'

a^2 = b^2 + c^2 - 2*b*c*cos(A)

a^2 = (12)^2 + (7)^2 - 2*(12)*(7)*cos(25.8)

a^2 = 144 + 49 - 168*0.900318771402194

a^2 = 144 + 49 - 151.253553595569

a^2 = 41.7464464044315

a = sqrt(41.7464464044315)

a = 6.46114900032738

a = 6.5

-----------------

Only one triangle is possible

The fully solved triangle has these angles and sides:

  • A = 25.8 (approx)
  • B = 126
  • C = 28.2 (approx)
  • a = 6.5 (approx)
  • b = 12
  • c = 7

With stuff in bold representing the terms we solved for previously. Attached below is an image of the fully solved triangle.

4 0
3 years ago
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