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Pani-rosa [81]
3 years ago
7

What is the answer?????

Mathematics
2 answers:
otez555 [7]3 years ago
6 0
The first one and the fourth one
Pani-rosa [81]3 years ago
4 0
The 1st and the 4th
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Match the expressions given in words with their values when m=6
Assoli18 [71]
Yes i am omg wow hey
7 0
3 years ago
3cis(5pi/4) in polar form
madreJ [45]
Rectangular form:
z = -2.1213203-2.1213203i

Angle notation (phasor):
z = 3 ∠ -135°

Polar form:
z = 3 × (cos (-135°) + i sin (-135°))

Exponential form:
z = 3 × ei (-0.75) = 3 × ei (-3π/4)

Polar coordinates:
r = |z| = 3 ... magnitude (modulus, absolute value)
θ = arg z = -2.3561945 rad = -135° = -0.75π = -3π/4 rad ... angle (argument or phase)

Cartesian coordinates:
Cartesian form of imaginary number: z = -2.1213203-2.1213203i
Real part: x = Re z = -2.121
Imaginary part: y = Im z = -2.12132034
8 0
3 years ago
Please help with problems 6 and 7.
monitta
6 is A and seven is B
7 0
3 years ago
Solve it:3/10×7/10=21/100
egoroff_w [7]
I'm gonna guess you're asking if the equation is true or false.
Well, the equation is True. 3/10 * 7/10 is 21/100, or in decimal form 0.21.
Converting 21/100 to a decimal is 0.21.
0.21 = 0.21.
21/100 = 21/100.
7 0
3 years ago
Determine whether 5, 238 is divisible by 2, 3, 4, 5, 6, 9, or 10.
Gelneren [198K]

Answer:

2, 3, 6

Step-by-step explanation:

Simply try each value using long division.

2:

Since 5,238 ends in an even number, that automatically means it is divisible by 2.

5238/2=2619

Now for 3:

5238/3=1746 no remainder or decimal, so 3 also works

4:

You can either do long division again with 4, or you can see if 5238 divided by 2 (5238/2) is also divisible by 2. Since 2619 doesn't end in an even number, 4 is a no go.

Long division 5238/4=1309.5 decimal here, so 4 isn't an answer

5:

This is also very easy, simply check if the number ends in 0 or 5. Since 5,238 does not, 5 doesn't work either.

6:

You can do the same thing as with 4, except this time trying to find if 5238 divided by 3 (5238/3) is divisible by 2. Since 1746 ends in an even number, 6 also works.

Long division: 5238/6=873

9:

You can do the same thing as with 6, except this time trying to find if 5238 divided by 3 (5238/3) is divisible by 3.

1746/3=548 with a remainder of 2, which means 9 doesn't work

Long division: 5238/9=548.66 repeating

10:

Finally, 10 is another easy one. Simply check if the number ends in 0. 5,238 does not, so 10 doesn't work.

5 0
2 years ago
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