Answer:
1st picture: (0,4)
The lines intersect at point (0,4).
2nd picture: Graph D
2x ≥ y - 1
2x - 5y ≤ 10
Set these inequalities up in standard form.
y ≤ 2x + 1
-5y ≤ 10 - 2x → y ≥ -2 + 2/5x → y ≥ 2/5x - 2
When you divide by a negative number, you switch the inequality sign.
Now you have:
y ≤ 2x + 1
y ≥ 2/5x - 2
Looking at the graphs, you first want to find the lines that intersect the y-axis at (0, 1) and (0, -2).
In this case, it is all of them.
Next, you would look at the shaded regions.
The first inequality says the values are less than or equal to. So you look for a shaded region below a line. The second inequality says the values are greater than or equal to. So you look for a shaded region above a line.
That would mean Graph B or D.
Then you look at the specific lines. You can see that the lower line is y ≥ 2/5x - 2. You need a shaded region above this line. You can see the above line is y ≤ 2x + 1. You need a shaded region below this line. That is Graph D.
There is no picture or anything but it’s ok .
The solution for this problem is:
We know the problem has the following given:
Sample size of 200
X = 182
And the probability of .9005; computation: 1 - .0995 = .9005
So in order to get the probability:
P (x >= 182) = 1 – 0.707134 = .292866 is the probability
that when 200 reservations
are recognized, there are more passengers showing up than there
are seats vacant.
The other solution is:
p (>= 182) = p(183) +
P(184) + P(185) + ... + P(199) + P(200) = 0.292866
Answer:
8(34a−1)
Step-by-step explanation:
Answer:
Not executable
Step-by-step explanation:
f(x) = a(x - h)² + k - vertex form of the equation of the parabola with vertex (h, k)
so the equation of parabola with the vertex (24, 10) is :
f(x) = a(x - 24)² + 10
the parabola's axis of symmetry parallel to the y-axis and passing through point (4,290) means: h = 4
<h3>
4 ≠ 24</h3>
That means you write something wrong in your question.
