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Lana71 [14]
4 years ago
8

Pls Answer Correctly, What is this Math Problem? Pls don't spam...

Mathematics
2 answers:
DENIUS [597]4 years ago
7 0

Answer: i sorry idk how to answer it

Step-by-step explanation:

r-ruslan [8.4K]4 years ago
4 0

226.4 ;)

Use PEMDAS.

hope this helpsdeddede

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A wall is 15 ft. High and 10 ft. From a house. Find the length of the shortest ladder which will just touch the top of the wall
Talja [164]

Answer:

the length of the shortest ladder is 11.41 feet

Step-by-step explanation:

The computation of the length of the shortest ladder is shown below:

AB^2 = AC^2 + BC^2

AB^2= (10)^2 + (5.5)^2

AB^2= 100 + 30.25

AB^2 = 130.25

AB = 11.41 feet

hence, the length of the shortest ladder is 11.41 feet

7 0
3 years ago
Angel Graham takes out a $150,000 mortgage. This is a 30-year at $725 per month. What is the total amount of interest that Angel
Liula [17]
Total paid
725×12×30
=261,000
Total interest
261,000−150,000
=111,000
7 0
4 years ago
Read 2 more answers
Match each function with the corresponding restrictions to its domain when p(x)=2x and q(x) = 2^x.
ASHA 777 [7]
Recall that the domain of a function is the set of all x values of the function for which the function is defined.

Given that
p(x)=2x and q(x)=2^x


Given that
r(x)= \frac{q(x)}{p(x)} = \frac{2^x}{2x}
For the function to be undefined, the denominator should be zero
i.e. 2x = 0 which means that x = 0
Thus, the domain of the function is all real values of x except 0.

Therefore, the restriction is x ≠ 0.


Given that
r(x)= \frac{1}{p(x)-q(x)} = \frac{1}{2x-2^x}
For the function to be undefined, the denominator should be zero
i.e.
2x-2^x=0 \\ 2^x=2x
For x = 2,
2^2 = 2(2)=4
Also, for x = 1
2^1 = 2(1)=2
Thus, the domain of the function is all real values of x except 1 and 2.

Therefore, the restriction is x ≠ 1, 2.

Given that
r(x)= \frac{1}{p(x)+16q(x)}=\frac{1}{2x+16(2^x)}
For the function to be undefined, the denominator should be zero
i.e.
2x+16(2^x)=0 \\ 2x+2^4(2^x)=0 \\ 2x+2^{4+x}=0
For x = -2,
2(-2)+2^{4-2}=-4+2^2=-4+4=0.
Thus, the domain of the function is all real values of x except -2.

Therefore, the restriction is x ≠ -2.


Given that
r(x)=p(x)\circ q(x)=p(q(x))=2(2^x)
There is no value of x, for which the function is undefined.
Thus, the domain of the function is all real values of x.

Therefore, there is no restrictions to the domain of the function.


Given that
r(x)= \frac{q(x)}{p(x)+2}=\frac{2^x}{2x+2}
For the function to be undefined, the denominator should be zero
i.e.
2x+2=0 \\ 2x=-2 \\ x = -1
Thus, the domain of the function is all real values of x except -1.

Therefore, the restriction is x ≠ -1.
6 0
3 years ago
Read 2 more answers
You sell tickets at school for fundraisers. You sold car wash tickets, silly string fight tickets and dance tickets – for a tota
vredina [299]
1858 is your right answer for your question
5 0
3 years ago
Which equation represents the line if m=-3/4 and b=2? (1 Point) O y=-2 + 2 x O x + 2 = 12 y = -x + 2 O y = - 2 x - 2​
nevsk [136]

Answer:

  • y = -3/4x + 2

Step-by-step explanation:

<u>Line formula in slope-intercept form:</u>

  • y = mx + b

<u>Given</u>

  • m = -3/4, b = 2

<u>Then the formula is:</u>

  • y = -3/4x + 2

None of the answer options match this

3 0
3 years ago
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