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SashulF [63]
3 years ago
7

Click on the y intercept. -X +4

Mathematics
1 answer:
Nataly [62]3 years ago
5 0

Answer:4


Step-by-step explanation: the last number is the y-int




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If A(-5,7), B(-4,-5), C(-1,-6) and D(4,5) are the vertices of a quadrilateral, find the area of the quadrilateral ABCD.
MrMuchimi
After plotting the quadrilateral in a Cartesian plane, you can see that it is not a particular quadrilateral. Hence, you need to divide it into two triangles. Let's take ABC and ADC.

The area of a triangle with vertices known is  given by the matrix
M = \left[\begin{array}{ccc} x_{1}&y_{1}&1\\x_{2}&y_{2}&1\\x_{3}&y_{3}&1\end{array}\right]

Area = 1/2· | det(M) |
        = 1/2· | x₁·y₂ - x₂·y₁ + x₂·y₃ - x₃·y₂ + x₃·y₁ - x₁·y₃ |
        = 1/2· | x₁·(y₂ - y₃) + x₂·(y₃ - y₁) + x₃·(y₁ - y₂) |

Therefore, the area of ABC will be:
A(ABC) = 1/2· | (-5)·(-5 - (-6)) + (-4)·(-6 - 7) + (-1)·(7 - (-5)) |
             = 1/2· | -5·(1) - 4·(-13) - 1·(12) |
             = 1/2 | 35 |
             = 35/2

Similarly, the area of ADC will be:
A(ABC) = 1/2· | (-5)·(5 - (-6)) + (4)·(-6 - 7) + (-1)·(7 - 5) |
             = 1/2· | -5·(11) + 4·(-13) - 1·(2) |
             = 1/2 | -109 |
<span>             = 109/2</span>

The total area of the quadrilateral will be the sum of the areas of the two triangles:

A(ABCD) = A(ABC) + A(ADC) 
               = 35/2 + 109/2
               = 72
8 0
4 years ago
two square regions have an area of 125 and 5 how many yards of fencing is needed to enclose? ( assume regions fenced separately)
nadya68 [22]

Answer:

24\sqrt{5}\ yards

Step-by-step explanation:

Let A1 be the area of one square and A2 be the area of second square

So,

A1 = s^2

where s is side of square

s^2=125\\\sqrt{s^2}=\sqrt{125}\\s=\sqrt{25*5}\\ s= \sqrt{5^2 * 5}\\ s= 5\sqrt{5}

So side of one square is 5\sqrt{5}

To calculate the length of fence we need to find the perimeter of the square

So,

P1 = 4 * s

=4*5\sqrt{5} \\=20\sqrt{5}

For second square:

A_2=s^2\\5=s^2\\\sqrt{s^2}=5\\{s}=\sqrt{5}

The perimeter will be:

P_2 = 4*s\\=4 * \sqrt{5} \\=4\sqrt{5}

So the total fence will be: P1+P2

= 20\sqrt{5}+4\sqrt{5} \\= 24\sqrt{5}\ yards

3 0
3 years ago
Convert 6.25 to degrees
Elenna [48]
I'm going to take a guess that you are wanting to convert 6.25 radians to degrees.  If I'm wrong, then ignore this!  Use the fact that 1 radian = 57.2958°.  Using the factor label method of conversion, we have 6.25r* \frac{57.2958deg}{1r}.  The radian label cancels leaving us with degrees.  6.25*57.2958=358.09°
4 0
3 years ago
What is the volume of the pyramid?<br> *Do NOT round your answer!
VashaNatasha [74]
Volume= 611 yd^3
Explanation=
V=L*W*H/3
V=10*13*14.1/3
V=611
5 0
3 years ago
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Translate the sentence into an inequality.
tamaranim1 [39]
3 Because 7 x 3 = 21 and 7 + 3 = 10

7 x w = 21 and 7 + w = 10
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3 years ago
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