Ask question

Ask question

All categories

3 years ago

13

Use the draw a diagram strategy to solve. Corbin read of the pages in his book. He has 42 pages left to read. How many pages did

he read already?

1 answer:

yKpoI14uk [10]3 years ago

8 0

How many pages are in the book

You might be interested in

If sin(theta) =4/5 and is in quadrant 2, the value of cot(theta

iren [92.7K]

$\sin\theta= \frac{4}{5} 
\\
\\\sin^2\theta+\cos^2\theta=1
\\ \cos\theta=\pm \sqrt{1-\sin^2\theta} =\pm \sqrt{1-( \frac{4}{5})^2 } =\pm \sqrt{1- \frac{16}{25} } =\pm \sqrt{\frac{9}{25} }=\pm \frac{3}{5}}$

$\theta \in II \Rightarrow \cos\theta\ \textless \ 0 \Rightarrow \cos\theta=-\frac{3}{5}$

$\cot\theta= \frac{\cos\theta}{\sin\theta}= \frac{-\frac{3}{5}}{\frac{4}{5}} =- \frac{3}{4}$

5 0

3 years ago

Estevan walks to school he usually stays on the sidewalk but today he cut through the park how much shorter did he walk today th

andrew-mc [135]

Is there any other info?

4 0

3 years ago

3.2y-1.4y+y-0.6y=0.55

Kazeer [188]

Answer:

it is y=0.25

Step-by-step explanation:

because Step 1: Simplify both sides of the equation.

3.2y−1.4y+y−0.6y=0.55

3.2y+−1.4y+y+−0.6y=0.55

(3.2y+−1.4y+y+−0.6y)=0.55(Combine Like Terms)

2.2y=0.55

2.2y=0.55

Step 2: Divide both sides by 2.2.

2.2y

2.2

=

0.55

2.2

8 0

3 years ago

A circle with radius of 4 cm sits inside a circle with radius of 11 cm.

kap26 [50]

The area of the shaded region = 330 sq cm

Step-by-step explanation:

Given,

The radius of small circle (r) = 4 cm

The radius of large circle (R) = 11 cm

To find the shaded region

Formula

The area of circle of radius r = π $r^{2}$ sq cm

So, The radius of the small circle = π× $4^{2}$ sq cm = 16π sq cm

The radius of the large circle = π× $11^{2}$ sq cm = 121π sq cm

Hence the area of the shaded region = 121π-16π sq cm

= 105π sq cm

= 105 × $\frac{22}{7}$ sq cm = 330 sq cm

5 0

3 years ago

Read 2 more answers

What is the quotient of (x3 - 3x2 + 5x – 3) = (x - 1)?

IRINA_888 [86]

Note: Consider "÷" sign instead of "=".

Given:

$(x^3-3x^2+5x-3)\div (x-1)$

To find:

The quotient.

Solution:

We have,

$(x^3-3x^2+5x-3)\div (x-1)$

It can be written as

$=\dfrac{x^3-3x^2+5x-3}{x-1}$

Splitting the middle terms, we get

$=\dfrac{x^3-x^2-2x^2+2x+3x-3}{x-1}$

$=\dfrac{x^2(x-1)-2x(x-1)+3(x-1)}{x-1}$

Taking out the common factor (x-1), we get

$=\dfrac{(x-1)(x^2-2x+3)}{x-1}$

Cancel the common factors.

$=x^2-2x+3$

The quotient is $x^2-2x+3$ .

Therefore, the correct option is D.

7 0

3 years ago

Read 2 more answers