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solmaris [256]
3 years ago
13

The class is planning a party the pizza restaurant cuts each pizza into 8 slices there are 32 students how many pizzas does ther

e class need to order for each student to have one slice? Explain
Mathematics
1 answer:
kobusy [5.1K]3 years ago
3 0
You would need 4 pizzas

Each pizza has 8 slices

4 pizzas means 8+8+8+8=32
Or 8x4=32
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Draw on a number line and show the direction of the inequalities<br> y ≥ 4
LekaFEV [45]

refer to the image given below:

4 0
2 years ago
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The equation p=1.5r graphed find price p, in dollars for r pounds of rice
disa [49]

Answer:

Hope that help you mark me brinilylist

Step-by-step explanation:

Given that 5 pounds of rice at a store cost $6.50.

Then 1 pound of rice at a store cost = $6.50/5= $1.3

So the equation for the cost can be written as:

C=1.3P just like we write equation y=mx

Now we have to graph the cost C, vs pounds of rice.

Variable for Pounds of rice is not given so let it be "P"

So let's make a table for the number of pounds (P) and cost (C)  we can graph the points from that table to get the final graph.

The Attached graph is the final graph.

3 0
3 years ago
Farm A has 120 sheep. of the sheep have lambs. Some of the sheep have 1 lamb and some of the sheep
Ainat [17]

Answer:

75/120 = 15/24 = 5/8

Step-by-step explanation:

3 + 5 = 8 There are 8 parts

120 / 8 = 15

15 X 5 = 75

There are 75 sheeps with 2 lambs

3 0
2 years ago
A Regional College uses the SAT to admit students to the school. The university notices that a lot of students apply even though
Aliun [14]

Answer:

0.191 is the probability that a group of 12 randomly selected applicants would have a mean SAT score that is greater than 525 but below the current admission standard of 584.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 500

Standard Deviation, σ = 100

n = 12

We are given that the distribution of SAT score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(greater than 525 but 584)

Standard error due to sampling =

\displaystyle\frac{\sigma}{\sqrt{n}} = \frac{100}{\sqrt{12}}

P(525 < x < 584) = P(\displaystyle\frac{525 - 500}{\frac{100}{\sqrt{12}}} < z < \displaystyle\frac{584-500}{\frac{100}{\sqrt{12}}}) = P(0.866 < z < 2.909)\\\\= P(z \leq 2.909) - P(z < 0.866)\\= 0.998 - 0.807 = 0.191 = 19.1\%

P(525 < x < 584) = 19.1\%

0.191 is the probability that a group of 12 randomly selected applicants would have a mean SAT score that is greater than 525 but below the current admission standard of 584.

3 0
3 years ago
The temperature dropped from 75° to 50° what is the percent decrease in the temperature
Soloha48 [4]
Percent change is

(New - old) / old

50 - 75 / 75

25 / 75 = .33333333....

To convert to a percent, multiply by 100

Percent decrease = 33.33%
4 0
3 years ago
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