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Digiron [165]
4 years ago
12

Write (27a^-3)^-2/3 in simpleset form

Mathematics
2 answers:
Luden [163]4 years ago
4 0

Answer:

a²/9  

Step-by-step explanation:

(27a⁻³) (-⅔) = 27^(-⅔) × (a⁻³)^(-⅔)

                  = (3³)^(-⅔) × a²

                  = 3⁻²a²

                  = a²/9

Alona [7]4 years ago
3 0

Answer:

write (27a^-3)^-2/3 in simpleset form

Step-by-step explanation:

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Please help me with geometry. Theres only 3 questions i need help with
Irina18 [472]
Dang bruh this is a tuff one
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3 years ago
Which of the following is not a possible number of solutions when solving a system of equations containing a quadratic and a lin
Ksivusya [100]
3.

You could probably look up a fancy explanation of why this is, by I just went the easy route.

1 is definitely possible.

2 is too!

(Sorry if the images are hard to see)

So the answer has got to be 3!

Hope this helps!

4 0
3 years ago
A rope is 84 meters long is cut int two pieces so that one piece is 18 meters longer than the other. What is the length of each
Tpy6a [65]

Answer:

33 meters

51 meters

Step-by-step explanation:

84-18= 66

66/2= 33

33+18= 51

Check your answer:

51+33=84

5 0
3 years ago
Read 2 more answers
In a rectangle the length is 2 cm longer than the width. If its length and width are both increase by 4 cm it's area is increase
Brums [2.3K]

Answer:

Length = 6 cm and width = 4 cm.

Step-by-step explanation:

Let the width be x, then the length is x + 2 cm and its area = x(x + 2).

The new width and length are x + 4 and x + 6, and the new area is

(x + 4)(x + 6).

So we have the equation:-

(x + 6)(x + 4) = x(x + 2) + 56

x^2 + 10x + 24 = x^2 + 2x + 56

10x - 2x = 56 - 24

8x = 32

x = 4 cm = width

and length = 4 + 2 = 6 cm





8 0
3 years ago
Find MO and PR <br> ............................................................
ddd [48]

MO = 12 and PR = 3

Solution:

Given \triangle M N O \sim \Delta P Q R.

Perimeter of ΔMNO = 48

Perimeter of ΔPQR = 12

MO = 12x and PR = x + 2

<em>If two triangles are similar, then the ratio of corresponding sides is equal to the ratio of perimeter of the triangles.</em>

$\Rightarrow \frac{\text{Perimeter of }\triangle MNO}{\text{Perimeter of }\triangle PQR} =\frac{MO}{PR}

$\Rightarrow \frac{48}{12} =\frac{12x}{x+2}

Do cross multiplication.

$\Rightarrow 48({x+2})= 12(12x)

$\Rightarrow 48x+96= 144x

Subtract 48x from both sides.

$\Rightarrow 48x+96-48x= 144x-48x

$\Rightarrow 96= 96x

Divide by 96 on both sides, we get

⇒ 1 = x

⇒ x = 1

Substitute x = 1 in MO an PR.

MO = 12(1) = 12

PR = 1 + 2 = 3

Therefore MO = 12 and PR = 3.

7 0
3 years ago
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