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Lelechka [254]
3 years ago
8

What is the relationship among the numbers and symbols in the expression (6 – 4) • 2? Choose all answers that are correct. A. Th

e difference between 6 and 4 is split in 2. B. The difference between 6 and 4 is doubled. C. The expression has a value equal to twice 4 subtracted from 6. D. The expression has a value that is twice as much as 6 minus 4. Question
Mathematics
1 answer:
leonid [27]3 years ago
3 0
B. the difference between 6 and 4 is doubled ,why? becuz 6-4 is 2 and 2 is doubled by 2 and u get 4 basically 2 times 2 is 4 ..hope this helps!
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Jake and Gloria are running on the track team. Gloria can run twice as many miles as
Tanzania [10]

Answer:

J+2J=12 so 3J=12 so J=4

Step-by-step explanation:

Use J to represent Jake's miles.

We know that Gloria's miles (G) is twice J, so G=2J

We also know that Jake and Gloria together ran 12 miles.

So we know, J+2J=12 or 3J=12   meaning J=4

So Jake runs 4 miles, and since Gloria is two times that she ran 8 miles.

6 0
3 years ago
Suppose that the length of a side of a cube X is uniformly distributed in the interval 9
Nastasia [14]

Answer:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

Step-by-step explanation:

Given

9 < x < 10 --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

v = x^3

For a uniform distribution, we have:

x \to U(a,b)

and

f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.

9 < x < 10 implies that:

(a,b) = (9,10)

So, we have:

f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

Solve

f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

Recall that:

v = x^3

Make x the subject

x = v^\frac{1}{3}

So, the cumulative density is:

F(x) = P(x < v^\frac{1}{3})

f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right. becomes

f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.

The CDF is:

F(x) = \int\limits^{v^\frac{1}{3}}_9 1\  dx

Integrate

F(x) = [v]\limits^{v^\frac{1}{3}}_9

Expand

F(x) = v^\frac{1}{3} - 9

The density function of the volume F(v) is:

F(v) = F'(x)

Differentiate F(x) to give:

F(x) = v^\frac{1}{3} - 9

F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}

F'(x) = \frac{1}{3}v^{-\frac{2}{3}}

F(v) = \frac{1}{3}v^{-\frac{2}{3}}

So:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

8 0
2 years ago
Preform the indicated operation.<br> 4/11 ÷ 4/9​
BartSMP [9]

Answer:

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Step-by-step explanation: i tried my best

4 0
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Four grey regular polygons join together as shown in the diagram<br><br> please answer part b
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Answer:

a=72° b = 6°

Step-by-step explanation:

answer is in pic

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2 years ago
4(m - 3) = 36 PLEASE STEP BY STEP EXPLANATION IN WORDS!
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Answer: 12

Step-by-step explanation:

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3 years ago
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