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Zielflug [23.3K]
3 years ago
7

Help me please and dont scam the points

Mathematics
1 answer:
kicyunya [14]3 years ago
4 0

Answer:

So the answer is 14 seconds.

Step-by-step explanation:

Median means the number in the middle, and 17 and 11 are in the middle. Because there's 2 numbers in the middle, you need to average them to find the answer.

17+11=28

28 / 2= 14. So the answer is <u>14 </u><u>seconds</u>.

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Multiply the following complex numbers: (-7+ ) and ( + i). Show all work and explain the steps you are taking in the work.
notka56 [123]

Answer:

Step-by-step explanation:

in complex number land there are two distict parts real.. the first number and imaginary.. the second number with the i

if your problem really only has a 7 and an i in it.. then it looks like below

7 * i  = 7i

but..I suspect you just left out a bit of the problem.. repost .. i'll answer it again if the problem is different that what you posted already  :)

8 0
2 years ago
4(−5z+2)+(−6) using distributive property
amid [387]

Answer:

Step-by-step explanation:

-20z+8+(-6)

-20z+2

7 0
3 years ago
Read 2 more answers
I NEED HELP PLEASE!!
prohojiy [21]
60% decimal = .6 fraction= 6/10
3/4 percent =75% (think of $$) decimal =.75
0.23 percent =23% fraction= 23/100
1/8 percent= 12.5 decimal = 0.125
18% decimal= .18 fraction= 18/100 (simplified to 9/50)
2/3 percent=0.6% repeating (so put a line over 6) decimal= 0.6 repeating aswell so do the same as last
Your welcome :)
5 0
3 years ago
Need help with this geometry question, solving for x and please explain the formula for this
Alborosie
Alright, so what we can take as a given is that arcDE/2= ∠CDE=2x+20 since the arc corresponding to the angle is 2*the angle. To solve for arcDE, we multiply both sides by 2 to get 2(2x+20)=4x+40=arcDE. Since the arcs in a circle add up to 360 degrees and we only have -20+30x and arcDE, we have -20+40+4x+30x=360 using the associative property. Simplifying, we get 20+34x=340. Subtracting 20 from both sides, we get 340=34x. Next, we can divide both sides by 34 to get 10=x. 
3 0
3 years ago
9. A large electronic office product contains 2000 electronic components. Assume that the probability that each component operat
Marysya12 [62]

Answer:

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it works correctly, or it does not. The probability of a component falling is independent from other components. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 2000, p = 1-0.995 = 0.005

Approximate the probability that five or more of the original 2000 components fail during the useful life of the product.

We know that either less than five compoenents fail, or at least five do. The sum of the probabilities of these events is decimal 1. So

P(X < 5) + P(X \geq 5) = 1

We want P(X \geq 5)

So

P(X \geq 5) = 1 - P(X < 5)

In which

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2000,0}.(0.005)^{0}.(0.995)^{2000} = 0.000044

P(X = 1) = C_{2000,1}.(0.005)^{1}.(0.995)^{1999} = 0.000445

P(X = 2) = C_{2000,2}.(0.005)^{2}.(0.995)^{1998} = 0.002235

P(X = 3) = C_{2000,3}.(0.005)^{3}.(0.995)^{1997} = 0.007480

P(X = 4) = C_{2000,4}.(0.005)^{4}.(0.995)^{1996} = 0.018765

P(X < 5) = P(X = 0) + `P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000044 + 0.000445 + 0.002235 + 0.007480 + 0.018765 = 0.0290

P(X \geq 5) = 1 - P(X < 5) = 1 - 0.0290 = 0.9710

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

4 0
3 years ago
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