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2 years ago

What value of X makes the equation true -7x - (-5-x) = -9(2x-1) -1

Mathematics

1 answer:

Bond [772]2 years ago

5 0

Answer:

x = 1/4

Step-by-step explanation:

-7x - (-5-x) = -9(2x-1) -1

-7x + 5 + x = -18x + 9 - 1

combine like terms:

-6x + 5 = -18x + 8

add 18x to each side of the equation:

12x + 5 = 8

subtract 5 from each side:

12x = 3

divide both sides by 12:

x = 3/12 = 1/4

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In ΔCDE, \text{m}\angle C = (4x-16)^{\circ}m∠C=(4x−16) ∘ , \text{m}\angle D = (6x-1)^{\circ}m∠D=(6x−1) ∘ , and \text{m}\angle E

borishaifa [10]

Answer:

m∠C = 44°

Step-by-step explanation:

In ΔCDE,

m∠C=(4x−16) ∘

m∠D=(6x−1) ∘

m∠E=(4x−13) ∘ .

The sum of angles in a triangle = 180°

Step 1

We solve for x

m∠C + m∠D + m∠E

(4x−16)° + (6x−1)° + (4x−13)° = 180°

4x - 16 + 6x - 1 + 4x - 13 = 180°

4x + 6x + 4x -16 - 1 - 13 = 180°

14x - 30 = 180°

14x = 180+ 30

14x = 210

x = 210/14

x = 15

Step 2

Find m∠C

m∠C = (4x−16)°

m∠C = (4 × 15 - 16)°

m∠C = (60 - 16)°

m∠C = 44°

3 0

2 years ago

For the school play, the advance tickets cost $3, while tickets at the door cost $5. Thirty more tickets were sold at door in ad

Talja [164]

Answer:

310 tickets were sold in advance before school pay and 340 door tickets were sold in advance.

Step-by-step explanation:

Given:

Let number of tickets sold in advance be 'x'.

Cost of advance ticket = $3

Cost of door tickets = $5

Also given:

Thirty more tickets were sold at door in advance

Hence number of door tickets sold = $x+30$

Total Money Collected = $2630

Now we can say that Total Money Collected is equal to sum of number of tickets sold in advance multiplied by Cost of advance ticket and number of door tickets sold multiplied by Cost of door tickets.

Framing in equation form we get;

$3x+(x+30)5=2630$

Solving the equation to find the value of x we get;

$3x+5x+150=2630$

Combining the like terms we get;

$3x+5x=2630-150\\\\8x= 2480$

Now Dividing 8 on both side using division property we get;

$\frac{8x}{8} =\frac{2480}{8}\\ \\x=310$

Substituting the value of x to find number of door tickets been sold.

number of door tickets sold = $x+30=310+30 =340$

Hence, 310 tickets were sold in advance before school pay and 340 door tickets were sold in advance.

8 0

2 years ago

How to do this????????????????????

nexus9112 [7]

C. x+6 is a factor

...............

5 0

2 years ago

Read 2 more answers

Find the sum or difference: (5w - 9) - 3 (8 - 2w)

astraxan [27]

Answer:11w-33

Step-by-step explanation:

(5w - 9) - 3 (8 - 2w)

(5w-9)-24+6w

5w+6w-9-24

11w-33

6 0

2 years ago

Read 2 more answers

Life Sciences: Weight. The average weight of a baby born in 1900 was 6 pounds 4 ounces. In 2000 the average weight of a newborn

Hitman42 [59]

Answer: The expected weight of babies in 2040 is 136.4 ounces.

Step-by-step explanation:

Since we have given that

Average weight of a baby born in 1900 = 6 pounds 4 ounces = $6\times 16+4=96+4=100\ ounces$

Average weight of a baby born in 2000 = 6 pounds 10 ounces = $6\times 16+10=96+10=106\ ounces$

So, the rate of change of birth weight in ounces per year would be

$\dfrac{106-100}{2000-1900}=\dfrac{6}{100}=0.06\ ounces/yr$

Since slope = 0.06

Let x be the year and y be the weight in ounces.

So, the equation of line would be

$y-100=0.06(x-1900)\\\\y-100=0.06x-114\\\\y-0.06x=-114+100\\\\y-0.06x=14$

Now, put x = 2040

So, it would become

$y-0.06\times 2040=14\\\\y-122.4=14\\\\y=14+122.4\\\\y=136.4\ ounces$

Hence, the expected weight of babies in 2040 is 136.4 ounces.

4 0

2 years ago