Part 1) Find the measures of angle BGEwe know that
The inscribed angle measures half of the arc it comprises.
so
angle BGE=(1/2)*[arc EB]
Part 2) Find the angle BDG
we know that
The measure of the external angle is the semi-difference of the arcs that it covers.
so
angle BDG=(1/2)*[arc GEB-arc GB]
Complete the square to rewrite the quadratic:
2 <em>x</em>² + 3 <em>x</em> + 5 = 2 (<em>x</em>² + 3/2 <em>x</em>) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + 9/16 - 9/16) + 5
... = 2 (<em>x</em>² + 3/2 <em>x</em> + (3/4)²) + 5 - 9/8
... = 2 (<em>x</em> + 3/4)² + 31/8
Any real number squared becomes non-negative, so the quadratic expression has a minimum value of 31/8, which is greater than 0, and so there are no (real) <em>x</em> for which <em>y</em> = 0.
It increased by 15 65-15=50
Answer:
3,6,9,12 is not geometric seuence
Step-by-step explanation:
The line in the middle is half the length of the line on the outside. Multiply the middle line by 2 and set it equal to the outside line.
2(x-3) = x + 6
Simplify:
2x -6 p x + 6
Add 6 to both sides
2x = x + 12
Subtract x from both sides:
X = 12
The answer is B) 12