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Lelechka [254]
4 years ago
14

In the cells of all human females, one X chromosome is inactivated. The opsin1 gene is on the X chromosome and is expressed in t

he retinal cells of the eye. Mutations in this gene cause the recessive trait of colorblindness. Most women who have one mutant allele of the opsin1 gene and one normal allele of the opsin1 gene (they are heterozygous) can still see color. What is the most likely explanation for this finding? a. The X with the mutant allele of the opsin1 gene is more likely to be inactivated because of the opsin1 mutation. b. Any mutations in the opsin1 gene on the active X can be corrected through genetic exchange (recombination) with the inactive X. c. If the active X has the mutant allele of opsin1 gene, the inactive X with the normal allele will be reactivated. d. Some retinal cells will have an active X with the mutant allele of the opsin1 gene, and some will have an active X with the normal allele of the opsin1 gene.
Biology
1 answer:
Vilka [71]4 years ago
6 0

Answer:

d. Some retinal cells will have an active X with the mutant allele of the opsin1 gene, and some will have an active X with the normal allele of the opsin1 gene.

Explanation:

X-inactivation (or silencing of X chromosome) is a process that occurs in females in order to prevent females from having twice as many X chromosome gene products as males. It occurs randomly during the embryonic development. Another important characteristic of X chromosome inacativation is that it occurs on a cellular level which leads to mosaic expression. This means that some cells will have an inactive maternal X-chromosome and some inactive paternal X-chromosome.

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A population of bacteria is experiencing exponential growth and doubles in population size every 20 minutes. If there was 1 bact
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6 0
3 years ago
Suppose two independently assorting genes are involved in the pathway that determines fruit color in squash. These genes interac
Vaselesa [24]

Answer:

120 white individuals

30 yellow individuals

10 green individuals  

Explanation:

Available data:

  • Dominant epistasis: Phenotypic frequencies 12:3:1
  • W allele codes for a dominant white phenotype
  • w allele codes for a colored squash
  • Y allele codes for a dominant yellow phenotype
  • y allele codes for a recessive green phenotype
  • W allele will always mask the phenotype produced by Y or y alleles
  • 160 offspring

Dihybrid Cross

Parental)   WwYy      x      WwYy

Gametes) WY   Wy    wY    wy

                 WY   Wy    wY    wy

Punnet Square)

                            WY         Wy        wY       wy

               WY     WWYY   WWYy   WwYY  WwYy

               Wy      WWYy   WWyy    WwYy  Wwyy

               wY      WwYY   WwYy    wwYY  wwYy

               wy       WwYy   Wwyy    wwYy  wwyy

F1 Phenotypic Frequency)

White phenotype: 12/16 = 120 individuals

Yellow phenotype: 3/16 = 30 individuals

Green Phenotype: 1/16 = 10 individuals

To know how many offspring are expected to have the white, yellow, and green phenotypes, you can perform a three simple rule. This is:

16 ------- 160 offspring

12 White ------- X = 120 offspring

3 Yellow ------- X= 30 offspring

1 Green --------X = 10 offspring              

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3 years ago
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Nonamiya [84]

NADH and carbon dioxide

7 0
3 years ago
The 9:3:3:1 phenotype ratio is expected in the f2 generation when question 3 options: the genes for the two traits assort indepe
Aneli [31]
<span>Answer: the genes for the two traits assort independently.
The proportion </span><span>9:3:3:1 is found when studying two genes at the same time,</span><span> known as a dihybrid cross. Mendel did this cross and found that the offspring, had 4 different phenotypes, but in different quantities . </span>This ratio led Mendel to develop the law of independent assortment.


6 0
4 years ago
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