What is the answer to 88 divided by 7936

Samuel solved the equation h - 234 = 1,192 and found the solution to be h = 958. Is he correct? If not, why not?

prohojiy [21]

Answer:

B.

Step-by-step explanation:

h -234 = 1,192

-234 is a negative and if you add a negative number with a positive you have subtract and the remaining is your answer.

1,192+234=1,426

1,426-234=1,192

h=1,426

4 0

3 years ago

In the 1970s, due to world events, there was a gasoline shortage in the United States. There were often long lines of cars wai

barxatty [35]

Answer:

Part A: The average car length is 9.1 feet to the nearest tenth foot

Part B: The line would be 9100 feet to contained 1000 cars

Step-by-step explanation:

* Lets explain how to solve the problem

# Part A:

- There were 62 cars in a line that stretched 567 feet

- The cars are lined up bumper-to-bumper

- That means there is no empty spaces between the cars

* To find the average length of the car we will divide the length of

the line by the numbers of the cars

∵ The average car length = length of the line/number of cars

∵ The length of the line is 567 feet

∵ The numbers of the cars is 62 cars

∴ The average car length = 567/62 = 9.1 feet

* The average car length is 9.1 feet to the nearest tenth foot

# Part B:

- There are 1000 cars

- We need to find the length of line which contained the cars

∵ The average car length = length of the line/number of cars

∵ The average of car length is 9.1 feet

∵ The number of the cars is 1000 cars

∴ 9.1 = length of the line/1000

- Multiply both sides by 1000

∴ The length of the line = 9.1 × 1000 = 9100 feet

∴ The line would be 9100 feet to contained 1000 cars

7 0

3 years ago

monica tiene 6/10kg de dulces con los cuales llena 1/4 de una bolsa de celofn ¿cual es la capacidad de la bolsa?

Anit [1.1K]

The question in English
<span>Monica has 6 /10 kg of candy with which she fills 1/4 of a cellophane bag. What is the capacity of the bag?
</span>
we know that
6/10---------> 0.60
1/4----------> 0.25------> 25%

if 25% of a cellophane bag---------------> has a 0.60 kg of candy
100%-----------------------------------------> X
X=100*0.60/25--------> X=2.4 kg

the answer is
2.4 kg

the answer in Spanish

Sabemos que
6/10---------> 0.60
1/4----------> 0.25------> 25%

if 25% de la bolsa de celofan---------------> se llena con 0.60 kg de dulces
100% de la bolsa----------------------------------------->se llenara con X kg
X=100*0.60/25--------> X=2.4 kg

La respuesta es
2.4 kg

5 0

3 years ago

3. A new process has been developed for applying pho toresist to 125-mm silicon wafers used in manufac turing integrated circu

dlinn [17]

Answer:

a

The null hypothesis is $H_o : \mu = 13.4000$

The alternative hypothesis is $H_a : \mu \ne 13.4000$

The null hypothesis is rejected

b

The 99% confidence level is $13.3930 < \mu < 13.3994$

Step-by-step explanation:

From the question we are told that

The sample size is n = 10

The population mean is $\mu = 13.4 000 \ angstroms$

The level of significance is $\alpha = 0.05$

The sample data is

13.3987, 13.3957, 13.3902, 13.4015, 13.4001, 13.3918, 13.3965, 13.3925, 13.3946, and 13.4002

Generally the sample mean is mathematically represented as

$\= x = \frac{13.3987+ 13.3957\cdots +13.4002 }{10}$

=> $\= x = 13.3962$

Generally the sample standard deviation is mathematically represented as

$\sigma = \sqrt{\frac{\sum (x_i - \= x)^2}{n} }$

=> $\sigma = \sqrt{\frac{ (13.3987 - 13.3962)^2 + (13.3987 - 13.3962)^2 + \cdots + (13.3987 -13.4002)^2 }{10} }$

=> $\sigma =0.0039$

The null hypothesis is $H_o : \mu = 13.4000$

The alternative hypothesis is $H_a : \mu \ne 13.4000$

Generally the test statistics is mathematically represented as

$z = \frac{\= x - \mu}{\frac{\sigma}{\sqrt{n} } }$

=> $z = \frac{13.3962 - 13.4000}{\frac{0.0039}{\sqrt{10} } }$

=> $z = 3.08$

Generally the p-value is mathematically represented as

$p-value = 2P( z > 3.08)$

From the z-table $P(z > 3.08)= 0.001035$

So

$p-value = 2* 0.001035$

$p-value = 0.00207$

So from the obtained value we see that

$p-value < \alpha$

Hence the null hypothesis is rejected

Consider the b question

Given that the confidence level is 99% then the level of significance is

$\alpha = (100 -99)\%$

=> $\alpha = 0.01$

Generally from the normal distribution table critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

=> $E = 2.58 * \frac{0.0039}{\sqrt{10} }$

=> $E = 0.00318$

Generally the 99% confidence interval is mathematically represented as

$13.3962 - 0.00318 < \mu < 13.3962 + 0.00318$

=> $13.3930 < \mu < 13.3994$

7 0

3 years ago

A rental truck cost $48 plus $0.40 per mile.

Natalija [7]

(a) If we let x be the number of miles and y be the total cost, the equation for relating the number of miles and the total cost would be,
y = 0.4x + 48

(b) If the rental cost is 60,
60 = 0.4x + 48
The value of x from the equation is 30.

(c) You may prepare the table of values by allowing x be any number and then solve for y until we arrive with an answer for y being equal to 60.

3 0

4 years ago