Answer:
Step-by-step explanation:
The key here is knowing that the equation of the line that passes through these points is same
Thus having (6,14) and (0,0), the slope is as follows;
m = y2-y1/x2-x1 = 0-14/0-6 = -14/-6 = 7/3
Now we can use this slope here to get the value of y in the question
All we need to do is tie write the equation of the line for between the points (6,14) and (2,y)
That would be;
7/3 = y-14/1-6
7/3 = y-14/-5
cross multiply;
-35 = 3(y-14)
-35 = -3y + 42
-3y = -35-42
-3y= -77
y = -77/3
y = 77/3
Do you mean
![3 \sqrt[3]{125}](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%20)
or
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20)
remember that
![\sqrt[n]{x^m}=x^\frac{m}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%3Dx%5E%5Cfrac%7Bm%7D%7Bn%7D)
resolve the
![\sqrt[3]{125}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D)
part first
![\sqrt[3]{125}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%3D)
![\sqrt[3]{5^3}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%5E3%7D%3D)
so
![3 \sqrt[3]{125}=3*5=15](https://tex.z-dn.net/?f=3%20%5Csqrt%5B3%5D%7B125%7D%3D3%2A5%3D15%20)
or
![\sqrt[3]{125} =5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B125%7D%20%3D5)
not sure which one you mean
the answer is 2• 137= 274
Answer:
-13a^2 + 170ab - 13b^2.
Step-by-step explanation:
1. 36(a+b)^2 - 49(a-b)^2
This is the difference of 2 squares: a^2 - b^2 = (a + b)(a - b).
36(a+b)^2 - 49(a-b)^2
= (6(a + b) + 7(a - b))( 6(a + b) - 7(a - b))
= (6a + 7a + 6b - 7b)( 6a - 7a + 6b + 7b)
= (13a - b)(-a + 13b)
If you require the expansion of this it is:
-13a^2 + 170ab - 13b^2.
Only if the individual doing the calculation makes a substantial mistake.
Any fraction with the same quantity in the numerator and denominator
always has the value of ' 1 ', (provided only that the quantity is not zero).
