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3 years ago

13

What value will make the equation true -21 - ? = 1and1/2

1 answer:

Alekssandra [29.7K]3 years ago

3 0

Answer:

the answer would be -21 - (-22 1/2)= 1 1/2

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Help help help!!!!!!!!! <br><br> 7√96m³

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Answer:

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3 years ago

Look at the following numbers: −2, −1, 0, 1 Which pair of numbers has a sum of zero? (5 points) Select one: a. 1, −1 b. −2, 0 c.

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Approximate the integral integral integral integral f(x, y) dA by dividing the rectangle R with vertices (0, 0), (4, 0), (4, 2),

amm1812

Answer:

Step-by-step explanation:

Approximate the integral $\int\int\limits_R {f(x,y)} \, dA$ by dividing the region $R$ with vertices (0,0),(4,0),(4,2) and (0,2) into eight equal squares.

Find the sum $\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i$

Since all are equal squares, so $\delta A_i=1$ for every $i$

$\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=f(x_1,y_1)\delta A_1+f(x_2,y_2)\delta A_2+f(x_3,y_3)\delta A_3+f(x_4,y_4)\delta A_4+f(x_5,y_5)\delta A_5+f(x_6,y_6)\delta A_6+f(x_7,y_7)\delta A_7+f(x_8,y_8)\delta A_8\\\\=f(0.5,0.5)(1)+f(1.5,0.5)(1)+f(2.5,0.5)(1)+f(3.5,0.5)(1)+f(0.5,1.5)(1)+f(1.5,1.5)(1)+f(2.5,1.5)(1)+f(3.5,1.5)(1)\\\\=0.5+0.5+1.5+0.5+2.5+0.5+3.5+0.5+0.5+1.5+1.5+1.5+2.5+1.5+3.5+1.5\\\\=24$

Thus, $\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=24$

Evaluating the iterate integral $\int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=\int\limits^4_0 {[xy+\frac{y^2}{2} ]}\limits^2_0 \, dx =\int\limits^4_0 {[2x+2]}dx\\\\=[x^2+2x]\limits^4_0=24.$

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3 years ago

Which is equivalent to RootIndex 5 StartRoot 1,215 EndRoot Superscript x?

SOVA2 [1]

Answer:

1,215 Superscript one-fifth x

Step-by-step explanation:

Given:

The expression to simplify is given as:

$(\sqrt[5]{1215})^x$

We know that,

$\sqrt[n]{a} = a^{\frac{1}{n}}$

Here, $n=5, a=1215$

So, $\sqrt[5]{1215} = 1215^{\frac{1}{5}}$

So, the above expression becomes:

$(\sqrt[5]{1215})^x = (1215^{\frac{1}{5}})^x$

Now, using the law of indices $(a^m)^n=a^{(m\times n)}$

Here, $a=1215,m=\frac{1}{5},n=x$

So, the expression is finally simplified to;

$=(1215)^{({\frac{1}{5}}\times x)}\\\\=(1215)^{\frac{1}{5}x}$

Therefore, the second option is the correct one.

$(\sqrt[5]{1215})^x$ = 1,215 Superscript one-fifth x

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3 years ago

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