Answer:
A -60i - 14j
Step-by-step explanation:
u = -9i + 8j
v = 7i + 5j
2u = 2(-9i + 8j) = -18i + 16j
6v = 6(7i + 5j) = 42i + 30j
2u - 6v
(-18i + 16j) - (42i + 30j)
(-18i - 42i) + (16j-30j)
-60i - 14j
Fractions Decimals Percents
1/4 0.25 25%
4/5 0.80 80%
3/4 0.75 75%
33/100 0.33 33%
1/10 0.10 10%
33/50 0.66 66%
1/8 0.125 12.5%
2/4 0.50 50%
Everything is put into order how it’s supposed to be on the chart! :) hope this helps you out a lot. Have a wonderful day❤️
Answer:
R=10,244 Lb
Step-by-step explanation:
In order to solve this problem, we can start by drawing the situation. (See attached picture).
We can look at the forces applied by the trucks as vectors, so in this case, in order to find the resultant force, we can add the two vectors. You can do so by drawing one force after the other and join the start of the first force with the end of the second force to form a triangle. The missing side will be the resultant force. In that triangle I drew there, the inner angle will be found by subtracting 180°-110°=70°
In this case we can find the resultant force by using the law of cosines:

so we can use the data given by the problem:

so we can solve this for R, so we get:

now we can substitute:

which yields:
R=10,244Lb