Question

6

Answer 1

The length of A"B" is 20 units

How to determine the length of A'B'?

From the figure, we have:

A = (1, 4)

B = (4, 8)

The distance AB is:

$AB = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2$

So, we have:

$AB = \sqrt{(1 -4)^2 + (4-8)^2$

Evaluate

$AB = \sqrt{25$

This gives

AB = 5

The scale factor of dilation is 4.

So, we have:

A'B' = 5 * 4

Evaluate

A'B' = 20

Hence, the length of A"B" is 20 units

Read more about dilation at:

brainly.com/question/18977334

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