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3 years ago

If g(c) = x^2-x, find g(2+h)-g(2)/h

1 answer:

6 0

g(c) = x^2-x
g(2) = 4 - 2 = 2
g(2+h) = (2+h)^2 - (2+h)
g(2+h) = 4 + 4h + h^2 - 2 -h
g(2+h) = h^2 + 3h + 2

g(2+h)-g(2)/h = ( h^2 + 3h + 2 - 2) / h
g(2+h)-g(2)/h = (h^2 + 3h) / h
g(2+h)-g(2)/h = h + 3

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3 years ago

The Length of a standard jewel case is 7cm more than its width. The area of the rectangular top of the case is 408cm. Find the l

salantis [7]

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The length of the case is 24 cm and its width is 17cm.

Step-by-step explanation:

The Length of a standard jewel case is 7cm more than its width.

Let the length be represented by L and the width be represented by W, this means that:

L = 7 + W

The area of the rectangular top of the case is 408cm². The area od a rectangle is given as:

A = L * W

Since L = 7 + W:

A = (7 + W) * W = 7W + W²

The area is 408 cm², hence:

408 = 7W + W²

Solving this as a quadratic equation:

=> W² + 7W - 408 = 0

W² + 24W - 17W - 408 = 0

W(W + 24) - 17(W + 24) = 0

(W - 17) (W + 24) = 0

=> W = 17cm or -24 cm

Since width cannot be negative, the width of the case is 17 cm.

Hence, the length, L, is:

L = 7 + 17 = 24cm.

The length of the case is 24 cm and its width is 17cm.

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3 years ago

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