Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;
Seperate the differential equation and solve for the constant C.
You have 100 rodents when:
You have 1000 rodents when:
Answer:
slope or m = -1
Step-by-step explanation:
The slope formula is:
y2-y1 -3 - 1 -4 -4
-------- = -------------- = --------- = ----- = -1
x2-x1 1 - (-3) 1+3 4
So, the slope is -1 XD YAY!!
Answer:
total payment = $563,760
Interest = $383,760
Principal part = $66
Step-by-step explanation:
(a) total payment:
n = 30 years = 360 months
monthly payment = $1,566
Total payment = $1,566 * 360 months = $563,760
(b) interest:
Total payment = $563,760
Principal = $180,000
Total payment = Principal + Interest
Interest = Total payment - Principal
Interest = $563,760 - $180,000 = $383,760
(c) part of first payment applied to the principal:
First payment = $1,566
Principal = $180,000
Interest rate = 10% yearly = 10% / 12 = 0.8333% = 0.008333 monthly
Monthly interest = Principal * Interest rate = $180,000 * 0.008333 = $1,500
Principal part = $1,566 - $1,500 = $66
Hope this helps!
Answer:
−8xf+16xg
Step-by-step explanation:
im not sure if thats correct but you should be using vector arithmetic to simplify the answer.
