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Anna71 [15]
3 years ago
5

Please help me I need this answer

Mathematics
1 answer:
Karolina [17]3 years ago
6 0

Answer:

11. x=10, y=14.1421356237

12. x=12.124355653, y=14

Step-by-step explanation:

11. Use tan and pythagorus

tanA=opposite/adjacent

tan45=x/10

10(1)=x

x=10

a²=b²+c²

y²=x²+10²

y²=10²+10²

y²=100+100

y=√200=14.1421356237

12. Use tan and pythagorus

tanA=opposite/adjacent

tan30=7/x

0.57735026919x=7

x=7/0.57735026919

x=12.124355653

a²=b²+c²

y²=x²+7²

y²=12.124355653²+7²

y²=147+49

y=√196=14

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The Thomas Supply Company Inc. is a distributor of gas-powered generators. As with any business, the length of time customers ta
Dmitry [639]

Answer:

The answer is below

Step-by-step explanation:

When computing quartile and decile, the data must be arranged in ascending order.

Given the data points:

13 13 13 20 26 26 29 31 34 34 35 35 36 37 38  41 41 41 42 43 46 47 48 49 53 55 56 62 67 82

The numbers are arranged in ascending order. The total number of terms is 30.

a)

First \ quartile(Q_1)=\frac{1}{4}(n+1)^{th}\  term\\\\where\ n=number\ of\ terms. Hence:\\\\Q_1=\frac{1}{4}(30+1)=7.75^{th}\ term=average\ of\ 7th\ and\ 8th\ term=\frac{29+31}{2} =30\\\\Q_1=30\\\\Third \ quartile(Q_3)=\frac{3}{4}(n+1)^{th}\  term\\\\Q_3=\frac{3}{4}(30+1)=23.25^{th}\ term=average\ of\ 23rd\ and\ 24th\ term=\frac{48+49}{2} =48.5\\\\Q_3=48.5

b)

Second \ decile(D_2)=\frac{2}{10}(n+1)^{th}\  term\\\\where\ n=number\ of\ terms. Hence:\\\\D_2=\frac{2}{10}(30+1)=6.2^{th}\ term=average\ of\ 6th\ and\ 7th\ term=\frac{26+29}{2} =27.5\\\\D_2=27.5\\\\\\Eight \ decile(D_8)=\frac{8}{10}(n+1)^{th}\  term=\frac{8}{10}(30+1)=24.8^{th}\ term\\=average\ of\ 24th\ and\ 25th\ term=\frac{49+53}{2} =51\\\\D_8=51

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3 years ago
What is the solution of the following system?
erica [24]

Answer:

The answer to your question is: both lines are the same.

Step-by-step explanation:

                                   

                                             3x + 3y = 10

                                            -9x -9y = -30

Elimination method

                                            9x + 9x = 30

                                           -9x -  9y = -30

                                              0     0      0

8 0
3 years ago
Solve each system of equations by graphing.<br> y = 2x<br> y = x + 1
yawa3891 [41]

Step-by-step explanation:

The system of linear equations are , (i) y = 2x and (ii) y = x + 1 . We will find some coordinates and then we will plot its graph. The point where both Graphs will meet will be the solution of the graph .

<u>•</u><u> </u><u>Findin</u><u>g</u><u> </u><u>coordinates</u><u> </u><u>of </u><u>Equ</u><u>ⁿ</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>:</u><u>-</u>

Step 1 : <u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

\tt y = 2x = 2(0) = \red{0}

Step 2: <u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

\tt y = 2x = 2(1) = \red{2}

\boxed{\begin{array}{c|c|c} \bf x & \tt 0 &\tt 1 \\ \bf y &\tt 0 & \tt 2 \end{array}}

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

<u>•</u><u> </u><u>Finding</u><u> </u><u>coord</u><u>inates</u><u> </u><u>of</u><u> </u><u>equⁿ</u><u> </u><u>(</u><u>ii</u><u>)</u><u> </u><u>:</u><u>-</u>

Step 1 : Put x = 0 :-

\tt y = x + 1  = 1 + 0  = \red{1}

Step 2: Put x = 1 :-

\tt y = x + 1 = 1 + 1 = \red{2}

\boxed{\begin{array}{c|c|c} \bf x & \tt 0 &\tt 1 \\ \bf y &\tt 1 & \tt 2\end{array}}

Now plot these points on the graph Taking appropriate scale . Refer to the attachment in graph . From graph the Solution is (1,2) .

8 0
3 years ago
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