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vampirchik [111]

3 years ago

15

Help needed please

1 answer:

ycow [4]3 years ago

6 0

To change a fraction to a decimal all u do it divide the numerator by the denominator

to change a decimal to a percent you multiple it by 100

to change a percent to a decimal you divide it by 100

and to change a decimal back to a fraction you see what place the last digit of the decimal ends in (maybe tenths, hundredths, or thousandths place) and if it's tenths you put it over 10, if it's hundredths place then put it over 100 and ect.

but if it has whole numbers just write it out and ignore it // ex. 1.25= 1 25/100= 1 1/4

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In 2009, the American Time Use Survey found that the average American spends 2.8 hours a day watching TV. Suppose the standard d

Anit [1.1K]

Answer:

4.72 hours/day

Step-by-step explanation:

Mean time spent watching TV (μ) = 2.8 hours a day

Standard deviation (σ) = 1.5 hours a day

The 90th percentile (upper 10%) of a normal distribution has an equivalent z-score of roughly z = 1.282. The minimum time spent watching TV, X, at the 90th percentile is:

$z=\frac{X-\mu}{\sigma} \\1.282=\frac{X-2.8}{1.5}\\ X=4.72\ hours/day$

On a typical day, you must watch at least 4.72 hours of TV to be in the upper 10%.

8 0

3 years ago

PLEASE HELP THIS IS DUE BY TOMORROW

Bezzdna [24]

Answer:b

Step-by-step explanation:

4 0

2 years ago

Find the midpoint of JK if J(-7. -5) and K(-3,7).

qaws [65]

Answer:

( − 5 , 1 )

Step-by-step explanation:

Use the midpoint formula to find the midpoint of the line segment.

7 0

3 years ago

How many solutions does the equation 4x + 2(x − 5) = 3(2x − 4) have? Group of answer choices infinitely many solutions no soluti

aleksandrvk [35]

Answer:

absolutley no solutions

Step-by-step explanation:

5 0

3 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago