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Dafna11 [192]
3 years ago
12

Can a triangle be formed with 4cm 8cm and 12cm

Mathematics
1 answer:
worty [1.4K]3 years ago
7 0
No. 4^2 + 8^2 or 16 + 64 is 80, and the hypotenuse, 12 (144) is not 80.
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True or false? A correct answer is worth (2 pts). Explain how you know for the additional (2 pts). Using complete sentence for (
PtichkaEL [24]

<u>answer (in words)</u>

FALSE. the coordinate pair (5, 2) is not a solution to the equation 2x+3y=10. in order to figure out whether or not the statement is true or false, plug the x and y values from the coordinate pair (5, 2) into the given equation, 2x+3y=10. if both sides of the equation end up equal, the coordinate pair is a solution to the equation. if not, the coordinate pair is not a solution to that equation.

<em>(i hope i explained that well enough, i'm better at explaining it algebraically as opposed to putting it into words lol)</em>

<u>answer (algebraic/steps for solving)</u>

first, plug in 5 for x in the equation 2x+3y=10.

  • 2x+3y=10 ⇒ 2(5)+3y=10

then plug in 2 for y.

  • 2(5)+3y=10 ⇒ 2(5)+3(2)=10

now your equation is 2(5)+3(2)=10. all that's left to do is to simplify. you can do this in whatever order you'd like, but i'll start with multiplying 2 · 5.

  • 2(5)+3(2)=10 ⇒ 10 + 3(2) = 10

multiply 3 · 2.

  • 10 + 3(2) = 10 ⇒ 10 + 6 = 10

add 10 + 6.

  • 10 + 6 = 10 ⇒ 16=10

16 and 10 are <em>not</em> equal, therefore (5, 2) is not a solution to the equation 2x+3y=10. in order for a coordinate pair to be the solution to an equation, both sides of the equation need to end up equal after solving and simplifying.

i hope this helps! have a great rest of your day <3

6 0
3 years ago
describe a situation in which a formula could be used more easily if it were rearranged. Include the formula in your description
pshichka [43]
I need to find the length of something when I am given the volume, width, and height.

v=lwh
l = v/wh

Hope this helps!
5 0
2 years ago
Read 2 more answers
3/8x + 6(x+3) = -5(1/4x - 1) + 6x find the solution pls
umka21 [38]

Answer:

x = -8

Step-by-step explanation:

Solve for x:

(3 x)/8 + 6 (x + 3) = 6 x - 5 (x/4 - 1)

Hint: | Put the fractions in x/4 - 1 over a common denominator.

Put each term in x/4 - 1 over the common denominator 4: x/4 - 1 = x/4 - 4/4:

(3 x)/8 + 6 (x + 3) = 6 x - 5 x/4 - 4/4

Hint: | Combine x/4 - 4/4 into a single fraction.

x/4 - 4/4 = (x - 4)/4:

(3 x)/8 + 6 (x + 3) = 6 x - 5(x - 4)/4

Hint: | Put the fractions in (3 x)/8 + 6 (x + 3) over a common denominator.

Put each term in (3 x)/8 + 6 (x + 3) over the common denominator 8: (3 x)/8 + 6 (x + 3) = (3 x)/8 + (48 (x + 3))/8:

(3 x)/8 + (48 (x + 3))/8 = 6 x - (5 (x - 4))/4

Hint: | Combine (3 x)/8 + (48 (x + 3))/8 into a single fraction.

(3 x)/8 + (48 (x + 3))/8 = (3 x + 48 (x + 3))/8:

(3 x + 48 (x + 3))/8 = 6 x - (5 (x - 4))/4

Hint: | Distribute 48 over x + 3.

48 (x + 3) = 48 x + 144:

(48 x + 144 + 3 x)/8 = 6 x - (5 (x - 4))/4

Hint: | Group like terms in 48 x + 3 x + 144.

Grouping like terms, 48 x + 3 x + 144 = (3 x + 48 x) + 144:

((3 x + 48 x) + 144)/8 = 6 x - (5 (x - 4))/4

Hint: | Add like terms in 3 x + 48 x.

3 x + 48 x = 51 x:

(51 x + 144)/8 = 6 x - (5 (x - 4))/4

Hint: | Put the fractions in 6 x - (5 (x - 4))/4 over a common denominator.

Put each term in 6 x - (5 (x - 4))/4 over the common denominator 4: 6 x - (5 (x - 4))/4 = (24 x)/4 - (5 (x - 4))/4:

(51 x + 144)/8 = (24 x)/4 - (5 (x - 4))/4

Hint: | Combine (24 x)/4 - (5 (x - 4))/4 into a single fraction.

(24 x)/4 - (5 (x - 4))/4 = (24 x - 5 (x - 4))/4:

(51 x + 144)/8 = (24 x - 5 (x - 4))/4

Hint: | Distribute -5 over x - 4.

-5 (x - 4) = 20 - 5 x:

(51 x + 144)/8 = (24 x + 20 - 5 x)/4

Hint: | Combine like terms in 24 x - 5 x + 20.

24 x - 5 x = 19 x:

(51 x + 144)/8 = (19 x + 20)/4

Hint: | Make (51 x + 144)/8 = (19 x + 20)/4 simpler by multiplying both sides by a constant.

Multiply both sides by 8:

(8 (51 x + 144))/8 = (8 (19 x + 20))/4

Hint: | Cancel common terms in the numerator and denominator of (8 (51 x + 144))/8.

(8 (51 x + 144))/8 = 8/8×(51 x + 144) = 51 x + 144:

51 x + 144 = (8 (19 x + 20))/4

Hint: | In (8 (19 x + 20))/4, divide 8 in the numerator by 4 in the denominator.

8/4 = (4×2)/4 = 2:

51 x + 144 = 2 (19 x + 20)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the right hand side:

51 x + 144 = 38 x + 40

Hint: | Move terms with x to the left hand side.

Subtract 38 x from both sides:

(51 x - 38 x) + 144 = (38 x - 38 x) + 40

Hint: | Combine like terms in 51 x - 38 x.

51 x - 38 x = 13 x:

13 x + 144 = (38 x - 38 x) + 40

Hint: | Look for the difference of two identical terms.

38 x - 38 x = 0:

13 x + 144 = 40

Hint: | Isolate terms with x to the left hand side.

Subtract 144 from both sides:

13 x + (144 - 144) = 40 - 144

Hint: | Look for the difference of two identical terms.

144 - 144 = 0:

13 x = 40 - 144

Hint: | Evaluate 40 - 144.

40 - 144 = -104:

13 x = -104

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 13 x = -104 by 13:

(13 x)/13 = (-104)/13

Hint: | Any nonzero number divided by itself is one.

13/13 = 1:

x = (-104)/13

Hint: | Reduce (-104)/13 to lowest terms. Start by finding the GCD of -104 and 13.

The gcd of -104 and 13 is 13, so (-104)/13 = (13 (-8))/(13×1) = 13/13×-8 = -8:

Answer: x = -8

5 0
3 years ago
Compare the ratios 2/11 and 3/12
valentinak56 [21]

Answer:

These are not equivalent

8 0
3 years ago
I need help with 10 11 and 12 PLEASEEEEE
Anit [1.1K]

Answer:

Angle 6 is 42 degrees

Angle Q is 56 degrees

Angle is 74 degrees

Let me know if this helps :)

4 0
3 years ago
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