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2 years ago

You have two cards with a sum of -12 in both hands.

Mathematics

1 answer:

aleksandrvk [35]2 years ago

4 0

A. -6 and -6 idk B sorry

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PLZZZ HELP ???????!!!!Asap

svetlana [45]

11 Is B.) 50 Miles Per Hour

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2 years ago

Read 2 more answers

Solve the inequality 171>-6x and graph the solution what does the graph look like

krok68 [10]

To solve the inequality, you need to isolate/get x by itself:

171 > -6x Divide -6 on both sides [dividing/multiplying a negative number on

-28.5 < x [dividing/multiplying a negative number in an inequality causes the sign (<, >, ≤, ≥) to flip]

-28.5 < x [x is a number greater than -28.5]

So your graph should have an open circle at -28.5 (the first small line next to -28), and the arrow pointing to the right since x is greater than -28.5 (increasing) The 1st option is your answer

[use the o---> and put it at -28.5]

7 0

2 years ago

A display of seed packets contains 24 zucchini seed packets and 28 other seed packets. What is the probability that a randomly s

Nonamiya [84]

Answer:

The probability is 6/13

Step-by-step explanation:

Number of zucchini seed packets = 24

Number of other seed packets = 28

Total number of packets = 24 + 28 = 52

Probability is given by

$P(E)=\frac{n(E)}{n(s)}\\\\n(E)=24,n(s)=52\\P(E)=\frac{24}{52}\\\\P(E)=\frac{6}{13}$

Hence, the required probability is 6/13

3 0

2 years ago

Dan has finished 2/3 of the 30 problems on an assignment

sleet_krkn [62]

Answer:

Step-by-step explanation:

7 0

2 years ago

OC and OR are similar. Find the length of QP.

Elena L [17]

Given:

Circle C and circle R are similar.

The length of arc AB is $s = \frac{22 \pi}{9}$

The radius of circle C (AC) = 4 unit

The radius of circle R (QR) =6 unit

To find the length of arc QP.

Formula

The relation between s, r and $\theta$ is

$arclength = 2\pi r \frac{\theta}{360}$

where,

s be the length of the arc

r be the radius

$\theta$ be the angle.

Now,

For circle C

Taking r = 4

According to the problem,

$2 \pi r \frac{\theta}{360} = \frac{22 \pi}{9}$

or, $2r \frac{\theta}{360} = \frac{22}{9}$ [ eliminating $\theta$ from both side]

or, $\theta = \frac{(22)(360)}{(9)(2)(4)}$

or, $\theta = 110^\circ$

Again,

For circle R

Taking, r = 6 and $\theta = 110^\circ$ we get,

The length of arc QP is

$arc length = 2\pi (6)(\frac{110}{360} )$

or, $arclength = \frac{11 \pi}{3}$

Hence,

The length of QP is $\frac{11 \pi}{3}$ . Option C.

5 0

2 years ago