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marin [14]
3 years ago
9

Calculate the speed of a 500.0 kilogram car that possesses 400,000 joules of kinetic energy.

Physics
1 answer:
lozanna [386]3 years ago
6 0

Answer: 40m/s

Explanation:

Given that,

speed of car (v) = ?

Mass of car (m) = 500.0 kilogram

Kinetic energy (KE) = 400,000 joules

Recall that kinetic energy is possessed by a moving object, and it depends on the mass and speed by which the object moves

i.e Kinetic energy = 1/2mv²

400,000J = 1/2 x 500.0kg x v²

400,000J = 250.0kg x v²

v² = 400,000J / 250.0kg

v² = 1600

Find the square root of v²

v = √1600

v = 40m/s

Thus, the speed of the car is 40m/s

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Why law of floatation is called the special condition of Archimedes principle​
Vinil7 [7]

Answer:

Archimedes principle: volume of water displaced by immersed object is equal to volume of water.

so if two object has same volume but different mass

then density determines the flotation of object,if an object has more density than water then it sinks.

I think this is called as special condition of floatation.

7 0
3 years ago
Current passes through a solution of sodium chloride. In 1.00 s , 2.68× 10 16 Na + ions arrive at the negative electrode and 3.9
Lady bird [3.3K]

Answer

a) charge of the sodium ion is,

q = n e

q = 2.68 x 10¹⁶ x 1.6 x 10⁻¹⁹

q = 4.288 x 10⁻³ C

charge of the chlorine ion is,

q' = n e

q' = 3.92 x 10¹⁶ x 1.6 x 10⁻¹⁹

q' = 6.272 x 10⁻³ C

the current

i = \dfrac{q}{t} + \dfrac{q'}{t}

i = \dfrac{4.288 \times 10^{-3}}{1} + \dfrac{6.272 \times 10^{-3}}{1}

i = 10.56 \times 10^{-3}

b) positive ion moves toward negative electrode hence direction of will be in the direction toward negative electrode.

5 0
3 years ago
At what angle do the cars move after the collision?
liubo4ka [24]

Answer:

his results in the final angle after the collision of 37.2 degrees basically what we did there is turn the vector into a right triangle. We use sohcahtoa to solve for the angle. Being.

Explanation:

6 0
2 years ago
Prečo je omnoho ľahšie udržať sa na hladine vody v mori ako v rieke
Vika [28.1K]

Answer:

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6 0
3 years ago
In serving, a tennis player accelerates a 59 g tennis ball horizontally from rest to a speed of 34 m/s Assuming that the acceler
Akimi4 [234]

Answer:

The magnitude of the force exerted on the ball by the racquet is 94.73 N.

Explanation:

The force exerted on the ball is the following:

F = ma

Where:

m: is the mass of the ball = 59 g

a: is the acceleration

The acceleration of the ball can be found with the following kinematic equation:

v_{f}^{2} = v_{0}^{2} + 2ad

Where:

d: is the distance = 0.36 m

v_{f}: is the final speed = 34 m/s

v_{0}: is the initial speed = 0 (it start from rest)

Hence, the acceleration is:

a = \frac{v_{f}^{2}}{2d} = \frac{(34 m/s)^{2}}{2*0.36 m} = 1605.6 m/s^{2

Finally, the force is:

F = ma = 59 \cdot 10^{-3} kg*1605.6 m/s^{2} = 94.73 N    

Therefore, the magnitude of the force exerted on the ball by the racquet is 94.73 N.                                

                                                                 

I hope it helps you!                                                              

6 0
3 years ago
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