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3 years ago

Arrange the planets from strongest magnetic field to weakest magnetic field. Jupiter Earth Venus

Physics

2 answers:

andre [41]3 years ago

8 0

Answer:

jupitar

Explanation:

Karo-lina-s [1.5K]3 years ago

4 0

The planets from strongest magnetic field to weakest magnetic field is Jupiter > Earth > Venus.

Magnetic fields are generated by the movement of magnetic material located in side the planet, usually at the core.

Jupiter, the biggest planet in our planetary system, likewise has the biggest magnetic field, producing a magnetosphere bigger than the Sun. It`s magnetic field is created by its fast rotation of 9.8 Earth hours. Dissimilar to Earth, Jupiter`s magnetic field is not produced by its core yet by interaction in its external core, which comprises of liquid metallic hydrogen.

Earth's magnetic field is produced by liquid metal at the center and Earth's fast pivot of 24 hours creates enough movement of the liquid to animate a magnetic field. While Venus does not have a magnetic field, likely on account of it's slow rate at around 243 Earth days, it's as yet shielded from sun oriented breezes utilizing an alternate kind of magnetism.

Therefore, the Jupiter have magnetic fields much stronger than that of the Earth and Venus.

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2 years ago

A player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory

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At the highest point in its trajectory, the ball's acceleration is zero but its velocity is not zero.

<h3>What's the velocity of the ball at the highest point of the trajectory?</h3>

At the highest point, the ball doesn't go more high. So its vertical velocity is zero.
However, the ball moves horizontal, so its horizontal component of velocity is non - zero i.e. u×cosθ.
u= initial velocity, θ= angle of projection

<h3>What's the acceleration of the ball at the highest point of projectile?</h3>

During the whole projectile motion, the earth exerts the gravitational force with a acceleration of gravity along vertical direction.
But as there's no acceleration along vertical direction, so the acceleration along vertical direction is zero.

Thus, we can conclude that the acceleration is zero and velocity is non-zero at the highest point projectile motion.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory

A- neither the ball's velocity nor its acceleration are zero.

B- the ball's acceleration points upward.

C- the ball's acceleration is zero but its velocity is not zero.

D- the ball's velocity points downward.

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2 years ago

a goalkeeper catches a 491 g soccer ball traveling horizontally at 29.4 m/s. if it took 2,218 n of force to stop the ball, how m

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The ball will take 2.551 seconds to reach its peak position.

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8 months ago

In the diagram, q1 = +6.60*10^-9 C and q2 = +3.10*10^-9 C. Find the magnitude of the total electric field at point P. pls help?

kirza4 [7]

Answer:

|E(t)| = 1258,46 [N/C]

α = 67,5⁰ (angle with respect x-axis)

Explanation:

E(t) Electric Field is a vector, so we need to determine module and direction

E(t) = E(q₁) + E (q₂) Where E(q₁) and E (q₂) are electric fields due to electric charge q₁ and q₂ respectively.

E(q₁) = K * q₁/ (d₁)² K = 9 *10⁹ [N*m²/C²] d₁ = 0,350 m

E(q₁) = 9 *10⁹ * 6,6*10⁻⁹ / 0,1225 [N*m²/C²] *C/m²

E(q₁) = 484,9 [N/C]

E(q₂) = 9 *10⁹ * 3,1*10⁻⁹ / 0,024025

E(q₂) = 1161,29

Then

|E(t)| = √ |Eq₁|² + |Eq₂|²

|E(t)| = √ ( 484,9)² +( 1161,29)²

|E(t)| = √ 235128 + 1348594,46

|E(t)| = 1258,46 [N/C]

And tanα = 1161,29/484,9 tanα = 2,395 α = 67,5⁰

The angle of the vector electric field with the x-axis

3 0

3 years ago

Read 2 more answers