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3 years ago

Look at the vector v plotted below.

Physics

2 answers:

melisa1 [442]3 years ago

4 0

Answer:

$\vec A = 2\hat i + 4\hat j$

Explanation:

As we know that the vector graphical representation is given in which it is inclined towards right by 2 units and inclined upwards by 4 units

so here we can say that

Part a)

X component of the vector is

$A_x = 2 units$

Part b)

Y component of the vector is

$A_y = 4 units$

Part c)

Vector form of the given representation is given as

$\vec A = 2\hat i + 4\hat j$

inessss [21]3 years ago

3 0

a) Imagine that it's raining towards Ox, so x-component is 2

b) Rain towards Oy: 4.

c) V=(2, 4)

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Where are globular clusters located in the milky way?.

mel-nik [20]

Answer:

Globular star clusters are located in the great spherical halo.

Explanation:

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8 0

2 years ago

Two charges are placed on the x axis. One of the charges (q1 = +7.7 µC) is at x1 = +3.1 cm and the other (q2 = -19 µC) is at x2

Alinara [238K]

Answer:

a) $E=50.53\times 10^{6}\ N/C$

The direction will be negative direction.

b) $E=268.22\times 10^{6}\ N/C$

The direction will be positive direction.

Explanation:

Given that

q1 = +7.7 µC is at x1 = +3.1 cm

q2 = -19 µC is at x2 = +8.9 cm

We know that electric filed due to a charge given as

$E=K\dfrac{q}{r^2}$

$E_1=K\dfrac{q_1}{r_1^2}$

$E_2=K\dfrac{q_2}{r_2^2}$

Now by putting the va;ues

$E_1=9\times 10^9\times \dfrac{7.7\times 10^{-6}}{0.031^2}\ N/C$

$E_1=72.11\times 10^{6}\ N/C$

$E_2=9\times 10^9\times \dfrac{19\times 10^{-6}}{0.089^2}\ N/C$

$E_2=21.58\times 10^{6}\ N/C$

The net electric field

$E=E_1-E_2$

$E=50.53\times 10^{6}\ N/C$

The direction will be negative direction.

As we know that electric filed line emerge from positive charge and concentrated at negative charge.

Now

distance for charge 1 will become =5.5 - 3.1 = 2.4 cm

distance for charge 2 will become =8.9-5.5 = 3.4 cm

$E_1=9\times 10^9\times \dfrac{7.7\times 10^{-6}}{0.024^2}\ N/C$

$E_1=120.3\times 10^{6}\ N/C$

$E_2=9\times 10^9\times \dfrac{19\times 10^{-6}}{0.034^2}\ N/C$

$E_2=147.92\times 10^{6}\ N/C$

The net electric field

$E=E_1+E_2$

$E=268.22\times 10^{6}\ N/C$

The direction will be positive direction.

7 0

3 years ago

A cart with a mass of 0.5 kg is at the top of the ramp. The height is 0.40m .

Tju [1.3M]

A=0.05.0M.

B=68.9244GPE.34

C=0

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3 years ago

What is the maximum number of electrons an oxygen atom can hold in its outer energy level?

gulaghasi [49]

The answer is 8.
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Answer:

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2 years ago