Answer:
<u>y = 139 + x³ + 17 </u>
Step-by-step explanation:
The word "sum" means the amount resulting from addition in an equation. This means that we are adding all of these numbers together.
The word "product" means the amount resulting from multiplication in an equation, this means we need to find the product of a number multiplied by itself three times. Since we don't know what number it is, we can use the variable 'x'.
So, you would be adding 139, the product of x³, and 17, which would be written as y = 139 + x³ + 17.
Answer:
= 3n + 3
Step-by-step explanation:
The sequence is arithmetic with explicit formula
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
From the recursive formula
a₁ = 6 and d = 3 [ the constant being added to A(n - 1) ] , then
= 6 + 3(n - 1) = 6 + 3n - 3 = 3n + 3
Answer:

Step-by-step explanation:
Coin toss:

Letter Selection:


X=37/5
or 7.4 in decimal form



now, with that template above in mind, let's see this one

A=3, B=1, shrunk by AB or 3 units, about 1/3
C=2, horizontal shift by C/B or 2/1 or just 2, to the left
D=4, vertical shift upwards of 4 units
check the picture below