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aleksandrvk [35]
4 years ago
4

A hot, wet summer is causing a mosquito population explosion in a lake resort area. The number of mosquitos is increasing at an

estimated rate of n(t) = 2100 + 10e0.9t per week (where t is measured in weeks). By how much does the mosquito population increase between the fifth and ninth weeks of summer? (Round your answer to three decimal places.) mosquitos
Mathematics
1 answer:
Iteru [2.4K]4 years ago
4 0

Answer:

n(4)=2465.982

Step-by-step explanation:

we have that n(t)=2100+10e^{0.9t} where t is measured in weeks and n(t) number of mosquitos

Find n(t) to t=4 (9tn week - 5th week = 4 weeks)

n(4)=2100+10e^{0.9*4} =2100+10e^{3.6}=2100+10*36.598243=2100+365.98243\\n(4)=2465.982

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Step-by-step explanation:

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Label the vertices of the quadrilateral A, B, C, D. Angle C is supplementary to the angle of measure 60 degrees, so its own measure is 120 degrees.

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HELP MATH QUESTIONS!! WILL MARK CORRECT ANSWERS BRAINLIEST!! 40 POINTS!! DUE TODAY ASAP!!
yuradex [85]

Answer:

  1. f(x) = 34.59 +3.74x
  2. 0.96
  3. very strong
  4. 8.93

Step-by-step explanation:

1. The selection of answers offers a choice of positive or negative slope, a slope of about 4 or about 35, and y-intercepts from the same set of values.

If you consider a couple of points (at the ends of the domain is usually a good choice), you see the slope is about 4 and the y-intercept is around 30.

For example, the points (5, 50) and (15, 91) have a slope of (91-50)/(15-5) = 4.1 so will give rise to the equation ...

  y -50 = 4.1(x -5)

Filling in x=0 gives y = 50 -20.5 = 29.5

So, the nearest of the offered choices is ...

  f(x) = 34.59 +3.74x

Please note that no calculator is involved. We simply estimated the parameters of the regression line based on a couple of the data points. This estimate is sufficient to allow us to find the correct answer choice.

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2. If we look at a few other data points, we see that they have a generally upward trend that matches the above equation pretty well. That suggests a very high value of correlation, so the appropriate choices would be 0.93 or 0.96. Of course, the correlation is positive, matching the sign of the slope of the regression line. (Since the data points do not fall exactly on a line, the correlation is not 1.00. My assessment is they fall close enough to the line to rate a correlation of .96 instead of .93.)

At this point, the output of your calculator can confirm that the correlation coefficient is closer to 0.96. Mine says r = 0.9624.

  r = 0.96

__

3. We have already determined by examining the data points that the correlation is "very strong." The correlation coefficient of 0.96 confirms this.

__

4. Using the equation of part 1, we can find the number of study hours:

  68 = 34.59 +3.74x

  (68 -34.59)/3.74 = x ≈ 8.933

We expect a score of 68 is associated with about 8.93 study hours.

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Please note that we have used very little calculation to determine the answers to this question. The only requirement is a general understanding of what linear regression and correlation coefficients mean.

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