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o-na [289]
3 years ago
14

Comparing Two Linear Functions Use the graph and table to answer the questions. Which vehicle loses the most value each year? Ca

r: 20 000 (2. 16500) 15 000 (G, 10900) Which vehicle will lose all of its value first? Value ($) 10.000 5000 6 8 If the truck's rate of depreciation changes to a decrease of $1,650 each year, which vehicle will lose all of its value first? Years Truck: Years: x Value ($) y 21,000 3 17,700 6 14.400
​

Mathematics
1 answer:
MakcuM [25]3 years ago
4 0

Answer:

Use the graph and table to answer the questions.

Which vehicle loses the most value each year?

Car

Which vehicle will lose all of its value first?

Car

If the truck’s rate of depreciation changes to a decrease of $1,650 each year, which vehicle will lose all of its value first?

Truck

Step-by-step explanation:

Ellabellasmella66
2 years ago
thank u so much u are super helpful
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Step-by-step explanation:

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I’m the triangle shown below what is the approximate value of x
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Answer:

The answer is choice B: 22.52 units.

Step-by-step explanation:

We use the Pythagoras's theorem which says for a right triangle with sides x,y and hypotenuse z:

x^2+y^2=z^2.

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z=26

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So we solve for x:

x=\sqrt{z^2-y^2}=\sqrt{26^2-13^2}  =\boxed{22.52\: units.}

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8 0
3 years ago
The quadratic function h(t)=-16.1t^2 + 150 models a balls height, in feet, over time, in seconds, after it is dropped from a 15
katrin [286]
<h2>Hello!</h2>

The answer is: The first graphic representation.

<h2>Why?</h2>

We are given a quadratic equation, meaning that it could be two possible solutions for the exercise, however, we are talking about time, so we have to consider only the obtained positive values.

Let's make the equation equal to 0 in order to find the values of "t"

h(t)=-16.1t^2 + 150\\0=-16.1t^2 + 150\\16.1t^2=150\\t^2=\frac{150}{16.1}=9.32\\t=+-\sqrt{9.32}=+-3.05\\t1=3.05\\t2=-305

So, discarding the negative value, we can use the possitive value to find the correct graphic representation.

To find the correct graphic representation we must take into consideration the following:

- We must remember that the sign of the coefficient of the quadratic term (t^2) will define if the parabola opens downward or upward.

From the given quadratic (or parabola) equation we have:

a=-1\\b=0\\c=150

So, since the coefficient of the quadratic term is negative, the parabola opens downward.

- Since we are looking for a graphic that represents the change in height over time, we need to look for a graphic that shows only positive values for the x-axis (time)

- We are looking for a parabola which y-axis intercept is equal to 150.

Therefore, the graphic representation of the quadratic function that models a ball's height over time is the first graphic representation.

Have a nice day!

8 0
3 years ago
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statuscvo [17]

Answer:

You will save 6,500

Explanation:

There are 52 weeks in one year multiply 52 times 125

5 0
3 years ago
Vector V is shown in the graph below.
Lady_Fox [76]

Answer:

v = -8i - 6j

Step-by-step explanation:

The starting point is (9, 9)

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The j is the vertical component.

Therefore, to go from the start to the end of the line, we need to travel negative 8 units (horizontally) and negative 6 units (vertically).

Therefore, v = -8i - 6j

8 0
2 years ago
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