Answer:
750 books
Step-by-step explanation:
Let there be "x" number of books in the 3rd room
Now,
2nd room has 3 times as 3rd room, so we can write:
Second Room = 3x
Also, there are 1960 MORE books in 1st room than 2nd room, so we can write:
First Room = 3x + 1960
In total there are 7210 books in all three rooms, thus we can write:
First Room + Second Room + Third Room = 7210
Now, replacing the first 2 equations in this, we get:
3x + 1960 + 3x + x = 7210
Solving for x:
![3x + 1960 + 3x + x = 7210\\7x=7210-1960\\7x=5250\\x=\frac{5250}{7}\\x=750](https://tex.z-dn.net/?f=3x%20%2B%201960%20%2B%203x%20%2B%20x%20%3D%207210%5C%5C7x%3D7210-1960%5C%5C7x%3D5250%5C%5Cx%3D%5Cfrac%7B5250%7D%7B7%7D%5C%5Cx%3D750)
"x" is indeed what we are looking for. Thus,
There are 750 books in the third room