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Licemer1 [7]
3 years ago
9

What is the inequality that represents the range of the function g(x)=-3/4x^2 when the domain is restricted to -4

Mathematics
1 answer:
enyata [817]3 years ago
4 0

Answer:

D

Step-by-step explanation:

to show the general direction of the graph, we should find the end points and one in the middle, lets see what happens why x is -4, 0, and 4. when x=-4, it is 16*-3/4 (which is negetive), when x is 0, y is 0, and when x is 4, the same this happens in the first number. If these points are plotted, it is shown as a parabola pointing downwards. The max is will be is 0. because before 0, the numbers are negetive in the y axis, and after they are negetive in the y axis, and it tops out at y=0 when x=0. Therefore Y is smaller than or equal to 0, or D.

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X times 3+6 when X equals four
Gekata [30.6K]

Step-by-step explanation:

4 x 3 + 6

12 + 6

= 18

or

4 x (3+6)

4 x 9

= 36

depends whether the 3+6 is in brackets :)

3 0
3 years ago
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Find the angle complementary to the angle 80°. A. 90° B. 180° C. 10° D. 100°
Alex_Xolod [135]

Complementary Angles is a pair of any two acute angles that add up to make 90 degrees


90-80 = 10

 the angle is 10 degrees

C is the correct answer

4 0
3 years ago
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Which value for x makes the sentence true? 1/10 + x = 1/7
alexandr1967 [171]

Answer:

3/70

Step-by-step explanation:

change 1/10 and 1/7 so the denominator (bottom number) is the same.  1/10= 7/70 and 1/7= 10/70 so you need 3/70 to make the two numbers equal.

6 0
3 years ago
LOTS OF POINTS GIVING BRAINLIEST I NEED HELP PLEASEE
Sidana [21]

Answer:

Segment EF: y = -x + 8

Segment BC: y = -x + 2

Step-by-step explanation:

Given the two similar right triangles, ΔABC and ΔDEF, for which we must determine the slope-intercept form of the side of ΔDEF that is parallel to segment BC.

Upon observing the given diagram, we can infer the following corresponding sides:

\displaystyle\mathsf{\overline{BC}\:\: and\:\:\overline{EF}}

\displaystyle\mathsf{\overline{BA}\:\: and\:\:\overline{ED}}

\displaystyle\mathsf{\overline{AC}\:\: and\:\:\overline{DF}}

We must determine the slope of segment BC from ΔABC, which corresponds to segment EF from ΔDEF.

<h2>Slope of Segment BC:</h2>

In order to solve for the slope of segment BC, we can use the following slope formula:

\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}  }

Use the following coordinates from the given diagram:

Point B:  (x₁, y₁) =  (-2, 4)

Point C:  (x₂, y₂) = ( 1,  1 )

Substitute these values into the slope formula:

\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{1\:-\:4}{1\:-\:(-2)}\:=\:\frac{-3}{1\:+\:2}\:=\:\frac{-3}{3}\:=\:-1}

<h2>Slope of Segment EF:</h2>

Similar to how we determined the slope of segment BC, we will use the coordinates of points E and F from ΔDEF to find its slope:

Point E:  (x₁, y₁) =  (4, 4)

Point F:  (x₂, y₂) = (6, 2)

Substitute these values into the slope formula:

\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{2\:-\:4}{6\:-\:4}\:=\:\frac{-2}{2}\:=\:-1}

Our calculations show that segment BC and EF have the same slope of -1.  In geometry, we know that two nonvertical lines are <u>parallel</u> if and only if they have the same slope.  

Since segments BC and EF have the same slope, then it means that  \displaystyle\mathsf{\overline{BC}\:\: | |\:\:\overline{EF}}.

<h2>Slope-intercept form:</h2><h3><u>Segment BC:</u></h3>

The <u>y-intercept</u> is the point on the graph where it crosses the y-axis. Thus, it is the value of "y" when x = 0.

Using the slope of segment BC, m = -1, and the coordinates of point C, (1,  1), substitute these values into the <u>slope-intercept form</u> (y = mx + b) to solve for the y-intercept, <em>b. </em>

y = mx + b

1 = -1( 1 ) + b

1 = -1 + b

Add 1 to both sides to isolate b:

1 + 1 = -1 + 1 + b

2 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 2.

Therefore, the linear equation in <u>slope-intercept form of segment BC</u> is:

⇒  y = -x + 2.

<h3><u /></h3><h3><u>Segment EF:</u></h3>

Using the slope of segment EF, <em>m</em> = -1, and the coordinates of point E, (4, 4), substitute these values into the <u>slope-intercept form</u> to solve for the y-intercept, <em>b. </em>

y = mx + b

4 = -1( 4 ) + b

4 = -4 + b

Add 4 to both sides to isolate b:

4 + 4 = -4 + 4 + b

8 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 8.

Therefore, the linear equation in <u>slope-intercept form of segment EF</u> is:

⇒  y = -x + 8.

8 0
3 years ago
Find the length of the third side. If necessary, round to the nearest tenth.<br> 6<br> 14
Romashka-Z-Leto [24]

Answer:

≈ 12.6

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let x be the third side, then

x² + 6² = 14²

x² + 36 = 196 ( subtract 36 from both sides )

x² = 160 ( take the square root of both sides )

x = \sqrt{160} ≈ 12.6 ( to the nearest tenth )

8 0
3 years ago
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