Example:
This suggests two solutions,
and
.
However, upon plugging these solutions back into the equation, you get
which checks out, but
does not because
is defined only for
(assuming you're looking for real solutions only). So, we call
an extraneous solution, and the complete solution set (over the real numbers) is
.
The area of the polygons compare to π in the way that as
more angles and sides are added to a polygon the polygon becomes closer to a
circle; the perimeter slowly changes to circumference. Π is used to find the
area and circumference of a circle, so as polygons come closer to becoming circles
π becomes more strongly associated to the polygon. You can even use π to find
the approximate area of a circle if you use the same formula (as you would to
find the area of a circle) on a polygon. Another way to go about it is like
this…
You can find the area of a circle if you know the circle’s
circumference by using these steps:
<span>1. Divide the
circumference by π to find the diameter of the circle.</span>
<span>2. Divide the
diameter by 2 to find the radius of the circle.</span>
<span>3. Now that you
have the radius you can use the formula Area= πr2 to find the area of the
circle.</span>
Answer:
88
Step-by-step explanation:
5GP= BP
2BNP= GNP
BP+BNP=333
GP+GNP=225
BNP= 333-BP
BNP= 333-5GP
GP= 225-GNP
GP= 225-2BNP
BNP=333-5(225-2BNP)
BNP=333-1125+10BNP
-9BNP=-792
BNP=88
Hope it helps :)
Mark Brainliest if possible.
Answer:
2.4
Step-by-step explanation:
