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2 years ago

6

How many terms are in the arithmetic sequence 1313, 1616, 1919, ……, 7070, 7373?

1 answer:

Ede4ka [16]2 years ago

3 0

The formula in getting the arithmetic sequence:
an = a1<span> + (n – 1)d.
</span>
We can substitute the values in order for us to know how many terms the sequence has.

an = 7373
a1 = 1313
d = 303

an = a1<span> + (n – 1)d
</span>7373 = 1313 + (n-1) 303
7373 = 1313 + 303n - 303
-303n = 1313 - 303 - 7373
303n = -1313 + 303 + 7373
303n = 6363
n = 21

So, there are 21 terms in the sequence given.

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