The very first step of the lowest cost method is to find the cell with the lowest cost in the entire matrix representing the cost of transportation along with supply and demand.
C. Find the cell with the lowest cost from the remaining (not crossed out) cells.
<u>Explanation:</u>
The second step in the lowest cost method is to allocate as many units as possible to that cell (having the lowest cost) without exceeding the supply or demand.
Then cross out the row or column (or both) that is exhausted by the assignment made. These two steps are further repeated until all the assignments are made and the total cost of transportation is calculated at the end.
Answer: JavaScript. What kind of script is used to run code on the client
A fuse protects computer system from voltage fluctuations
/* package whatever; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
class NestedLoops {
public static void main (String [] args) {
int numRows = 4;
int numCols = 5;
int i,j;
char ch = 'A';
// Note: You'll need to declare more variables
/* Your solution goes here */
for ( i = 0; i < numRows; i++) { // Outer loop runs for numRows times
for ( j = 0; j < numCols; j++) { // Inner loop runs for numCols times
System.out.print(i+1);
System.out.print((char)(ch+j));
System.out.print(" ");
}
}
System.out.println("");
return;
}
}
