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sveta [45]
3 years ago
7

No links or anything

Mathematics
1 answer:
Soloha48 [4]3 years ago
6 0

Answer:

1. 38, 80, 89 and 4. 14, 15, 29

I don't know if there is supposed to be only one, but both of those do not form right triangles.

Step-by-step explanation:

Evaluate all of them and see if they meet the requirements of the Pythagorean Theorem, a² + b² = c².

1. 38, 80, 89

a² + b² = c²

38² + 80² = 89²

1444 + 6400 = 7921

7844 ≠ 7921.

This is an answer because it doesn't satisfy the Pythagorean Theorem.

2. 16, 63, 65

a² + b² = c²

16² + 63² = 65²

256 + 3969 = 4225

4225 = 4225

This isn't the answer because it satisfies the Pythagorean Theorem.

3. 36, 77, 85

a² + b² = c²

36² + 77² = 85²

1296 + 5929 = 7225

7225 = 7225

This isn't the answer because it satisfies the Pythagorean Theorem.

4. 14, 15, 29

a² + b² = c²

14² + 15² = 29²

196 + 225 = 841

421 ≠ 841

This is an answer because it does not satisfy the Pythagorean Theorem.

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Answer:

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Step-by-step explanation:

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4 years ago
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3 0
3 years ago
4x-2y=14
Blababa [14]
4x - 2y = 14
y = 0.5x -1

Get just one variable on one side for both equations.

4x - 2y = 14 ⇒ 4x = 2y + 14 ⇒ 4x - 14 = 2y
y = 0.5x - 1 ⇒ x - 2 = 2y

Use the transitive property and then solve for x.

x-2 = 4x-14
12 = 3x
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<em>Edit: Apprently I didn't use substitution. Oops! Sorry...</em>
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