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zheka24 [161]
3 years ago
13

Your friend has a Lenovo IdeaPad N580 laptop, and the hard drive has failed. Her uncle has offered to give her a working hard dr

ive he no longer needs, the Toshiba MK8009GAH 80-GB 4200-RPM drive. Will this drive fit this laptop? Why or why not?a. Yes, the drive form factor and interface connectors match.b. No, the drive form factor matches but the interface does not match.c. Yes, the drive form factor, spindle speed, and interface all match.d. No, the drive form factor and interface do not match.
Computers and Technology
1 answer:
KengaRu [80]3 years ago
3 0

<u>Solution:</u>

It will not fit on Lenovo Ideapad N580.

The Ideapad N580 will fit HDD of form factor 2.5" (2.5 Inch) but the form factor of Toshiba mk8009GAH is 1.8" hence won't fit in the slot.

The interface type specifies which type of connector used to connect the motherboard and the HDD and it should be the same in order to use on it.

Ideapad uses the SATA interface type to connect the HDD but the Toshiba mk8009GAH is having an ATA type interface on it hence they cannot be connected with each other.

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Answer:

Following are the program in python language

def prob3_6(k): #function definition

  c = 0 #variable declaration

  while k != 1: #iterating the while loop

      print(k) #print k

      if k % 2 == 0:#check if condition  

          k= k // 2 #divisible by 2

      else: #else condition

          k = k * 3 + 1  

      c = c + 1

  print(k) #print k

  print c #print count

prob3_6(3)#function call

Output:

3

10

5

16

8

4

2

1

7

Explanation:

Following are the description of program

  • Create a function "prob3_6" in this function we passing an integer parameter of type "int" named "k".
  • Inside that function we declared a variable "c" of type "int" that is used for counting purpose .
  • After that we iterated the while for print the value of when it is not equal to 1 .
  • We check if condition when k gives 0 on modulus then k is divisible by 2 otherwise else block will be executed in the else part we multiply by 3 to k and add 1 to the k variable .
  • Finally print "k" and "c"

5 0
3 years ago
You want to make it possible for your smartphone to share its internet access wirelessly with your friends device which of the f
IrinaVladis [17]

Answer:WiFi or hotspots

Explanation:you will have to turn on your WiFi or hotspots on your smart phone and allow your friend to also turn his WiFi or hotspot after you will search for your WiFi and connect there he can use the internet

6 0
3 years ago
What are the pros and cons of using ICT​
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Answer:

Communication - Speed / time – money can be saved because it's much quicker to move information around. ...

Globalization - Video conferencing saves money on flights and accommodation. ...

Cost effectiveness - It feels free to send an email (although it isn't); it's without doubt cheaper than phone calls.

Explanation:

4 0
2 years ago
Why header files are needed in every c program ?expalin​
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Answer:

Header files serve two purposes. System header files declare the interfaces to parts of the operating system. You include them in your program to supply the definitions and declarations you need to invoke system calls and libraries.

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2 years ago
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For f
julia-pushkina [17]

Complete Question:

Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?

Answer:

a) 51.2 msec.  b) 5.12 msec

Explanation:

If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:

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The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:

a) BW  = 1 Mbps = 10⁶ bps

⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec

b) BW = 10 Mbps = 10⁷ bps

⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec

5 0
3 years ago
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