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Maru [420]
3 years ago
7

What is the length of PQ round to the nearest tenth of a unit p(-3 ,7) q(6 ,1)

Mathematics
2 answers:
Tema [17]3 years ago
7 0

Answer: The approximate length of PQ is 10.8 unit.

Step-by-step explanation:

Here the coordinates of point P are (-3,7) and the coordinates of Q are (6,1)

Thus, by the distance formula,

The distance between the points P and Q is,

PQ = \sqrt{(6-(-3))^2+(1-7)^2}

=\sqrt{(6+3)^2+(-6)^2

=\sqrt{9^2+ 36}

=\sqrt{81+36}=\sqrt{117}=10.8166538264\approx 10.8

Thus, the approximate length of PQ is 10.8 unit.

elixir [45]3 years ago
3 0

Answer:10.8 units

Step-by-step explanation:

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Answer: Memo would be 35 and Tecatito would be 17

Explanation:

17 + (17x2 +1) =52

17 + 35 = 52

Hope this helps!

4 0
3 years ago
6.Suppose the Gallup Organization wants to estimate the population proportion of those who think there should be a law that woul
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Answer:

A sample of n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2 is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In a previous study of 1012 randomly chosen respondents, 374 said that there should be such a law.

This means that n = 1012, \pi = \frac{374}{1012} = 0.3696

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

How large a sample size is needed to be 95% confident with a margin of error of E?

A sample size of n is needed, and n is found when M = E.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

E = 1.96\sqrt{\frac{0.3696*0.6304}{n}}

E\sqrt{n} = 1.96\sqrt{0.3696*0.6304}

\sqrt{n} = \frac{1.96\sqrt{0.3696*0.6304}}{E}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2

n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2

A sample of n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2 is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

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Answer:

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Step-by-step explanation:

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