12.589 en numeros romanos
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Solution
The table below is the required sample space of the to fair die
From the above table
The sample space contain 36 outcomes
Event A: The sum is greater than 9
we will look at the table and count all the elements that are greater than 9
There are 6 elements (they are 10, 10, 10, 11, 11, 12 from the table)
The probability for event A will be
P(A) = 1/6
Event B: The sum is an even number.
We will look at the table and count the number of elements that are even
There are 18 elements (notice that there are 3 even number on each of the 6 rows of the table)
The probability for event B will be
p(B) = 1/2
