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Colt1911 [192]
3 years ago
10

Given: -3x + y = 1. Write the equation in general form Ax + By + C =0.

Mathematics
1 answer:
Volgvan3 years ago
8 0
I think it would be -3x+y-1=0
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Provide a solution for the following equation: 3x + 2y=4
shtirl [24]

Answer:

One solution is to find x and y by doing the following:

Step-by-step explanation:

Let's solve for x.

3x+2y=4

Step 1: Add -2y to both sides.

3x+2y+−2y=4+−2y

3x=−2y+4

Step 2: Divide both sides by 3.

x=-2/3y+4/3

Lets solve for y.

3x+2y=4

Step 1: Add -3x to both sides.

3x+2y+−3x=4+−3x

2y=−3x+4

Step 2: Divide both sides by 2.

y= -3/2x+2

7 0
3 years ago
Data Set #1
Harman [31]

Answer:

The data table is attached below.

Step-by-step explanation:

The average of a set of data is the value that is a representative of the entire data set.

The formula to compute averages is:

\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{x_{i}}

Compute the average for drop 1 as follows:

\bar x_{1}=\frac{1}{3}\times[10+11+9]=10

Compute the average for drop 2 as follows:

\bar x_{2}=\frac{1}{3}\times[29+31+30]=30

Compute the average for drop 3 as follows:

\bar x_{3}=\frac{1}{3}\times[59+58+61]=59.33

Compute the average for drop 4 as follows:

\bar x_{4}=\frac{1}{3}\times[102+100+98]=100

Compute the average for drop 5 as follows:

\bar x_{5}=\frac{1}{3}\times[122+125+127]=124.67

The data table is attached below.

3 0
3 years ago
Use the law of cosines to find the value of 2*4*5 cos theta
sweet-ann [11.9K]
We can proceed in solving the problem since all information are given such as 2*4*5costheta.
we have a=4, b=5, and C=theta
let us solve for "c" using Pythagorean
c²=a²+b²
c²=4²+5²
c=6.4
Solving for theta or C
c²=a²+b²-2abcosC
6.4²=4²+5²-2*4*5*cosC
C=90

3 0
3 years ago
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Stephanie sells 12 pretzels per hour. Robert sells 15 pretzels per hour. This week, Robert sold an additional 18 pretzels. Which
Aleonysh [2.5K]

Answer:

I'm pretty sure it is D I'm not 100% sure though... sorry if it is wrong

5 0
3 years ago
Subtract 75% of 86 ft
ratelena [41]
75% of 86ft would be 64.5
Hope this helps. :)
3 0
3 years ago
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