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3 years ago

What are the possible factors of 39

Mathematics

2 answers:

Marizza181 [45]3 years ago

8 0

1,3,13,39 are possible factors

marissa [1.9K]3 years ago

3 0

Answer:

1, 3, 13 and 39

Step-by-step explanation:

<u>Factors</u> are those numbers which divide the given number without leaving any remainder.

So, here 39 can be divided by 1,3,13 and by 39 itself.

HOPE IT IS USEFUL

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3 years ago

One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p

scZoUnD [109]

Answer:

$c^2 = 9dp$

Step-by-step explanation:

Given

$dx^2 + cx + p = 0$

Let the roots be $\alpha$ and $\beta$

So:

$\alpha = 2\beta$

Required

Determine the relationship between d, c and p

$dx^2 + cx + p = 0$

Divide through by d

$\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0$

$x^2 + \frac{c}{d}x + \frac{p}{d} = 0$

A quadratic equation has the form:

$x^2 - (\alpha + \beta)x + \alpha \beta = 0$

So:

$x^2 - (2\beta+ \beta)x + \beta*\beta = 0$

$x^2 - (3\beta)x + \beta^2 = 0$

So, we have:

$\frac{c}{d} = -3\beta$ -- (1)

and

$\frac{p}{d} = \beta^2$ -- (2)

Make $\beta$ the subject in (1)

$\frac{c}{d} = -3\beta$

$\beta = -\frac{c}{3d}$

Substitute $\beta = -\frac{c}{3d}$ in (2)

$\frac{p}{d} = (-\frac{c}{3d})^2$

$\frac{p}{d} = \frac{c^2}{9d^2}$

Multiply both sides by d

$d * \frac{p}{d} = \frac{c^2}{9d^2}*d$

$p = \frac{c^2}{9d}$

Cross Multiply

$9dp = c^2$

$c^2 = 9dp$

Hence, the relationship between d, c and p is: $c^2 = 9dp$

8 0

3 years ago

I just can't do this

Roman55 [17]

You can, it's not as hard as you might think

simply multiply the speed by the fraction of time

23 × 1/5 = 23/5 = 4 3/5 = 4.6

$4.6 \: miles$

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3 years ago

PLEASE HELP I WILL GIVE YOU POINTS,BRAINLIEST, AND A COOKIE !!

Anna007 [38]

Answer:

20 maybe

Step-by-step explanation:

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3 years ago

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