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3 years ago

I don't quite understand the LCD and the unlike denominators properly. May someone explain it, please.

Mathematics

1 answer:

Whitepunk [10]3 years ago

5 0

Hey!

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LCD stands for Lowest Common Denominator.

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Explanation:

So let's say we have the equation 1/9 * 16/27

We want to find the LCD of both fractions. To find the LCD of both fractions find a the lowest common denominator in both fractions.

In this equation the lowest common denominator is 27 because 9 can go in 27 and 27 can go into itself. Se basically 27 is the lowest possibly common denominator both fractions can get to.

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Hope This Helped! Good Luck ;)

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Using this equation, when 38 passes are thrown, the expected yardage is of 318 yards.

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In the context of this problem, the input and output are given as follows:

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Output: number of passing yards obtaining by Mahomes/KC.

The points to be inserted in the calculator are given as follows:

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Hence the equation is given by:

y = 22x - 518.

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More can be learned about linear regression at brainly.com/question/22992800

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1 year ago

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3 years ago

Explain how you use a quick picture to find the quotient and remainder

Varvara68 [4.7K]

Example question: There are 38 students in a baseball club. The coach needs to split them up into equal groups of 4. How many groups can be made? How many kids are left over?
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3 years ago

Read 2 more answers

If f (n)(0) = (n + 1)! for n = 0, 1, 2, , find the taylor series at a=0 for f.

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Given that $f^{(n)}(0)=(n+1)!$ , we have for $f(x)$ the Taylor series expansion about 0 as

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(n+1)!}{n!}x^n=\sum_{n=0}^\infty(n+1)x^n$

Replace $n+1$ with $n$ , so that the series is equivalent to

$f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}$

and notice that

$\displaystyle\frac{\mathrm d}{\mathrm dx}\sum_{n=0}^\infty x^n=\sum_{n=1}^\infty nx^{n-1}$

Recall that for $|x|$ , we have

$\displaystyle\sum_{n=0}^\infty x^n=\frac1{1-x}$

which means

$f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}=\frac{\mathrm d}{\mathrm dx}\frac1{1-x}$
$\implies f(x)=\dfrac1{(1-x)^2}$

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3 years ago

The sum of two integers is 26. the sum of the squares of the two integers is 340. what is the product of the two numbers?

Phoenix [80]

Lets say that the two unknown integers are $n$ and $m$ .

We know the following things about $n$ and $m$ :

$n+m=26$
$n^2+m^2=340$

And, we want to find $nm$ .

To solve this, we'll use the expansion of the squared of the sum of any two inegers; this is expressed as:

$(n+m)^2=n^2+2nm+m^2$

So, given what we know about the unknown integers, the previous can be written as:

$(26)^2=340+2nm$

We can easily solve for $nm$ :

$nm= \frac{(26)^2-340}{2}= \frac{676-340}{2}= \frac{336}{2}=168$

The answer is 168.

Another approach to solve the problem is, from the two starting equations, compute the values of $n$ and $m$ , which are 12 and 14, and directly compute their product; however, the approach described is more elegant.

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3 years ago