Answer:
Zero solutions; there are no variables and thus there are no solutions
Step-by-step explanation:
We start out with the equation 9 (x - 3) + 15 = 9x - 11
Which simplifies to 9x - 27 + 15 = 9x - 11
The 9x terms cancel each other out, and we're left with 15 - 27 = -11
And we end up with -12 = -11, which is not true.
This tells us that the equation has zero solutions, because no matter what value we substitute for x, the equation will not be true.
<h3>
Answer:</h3>
B. (5, -2)
<h3>
Step-by-step explanation:</h3>
Try the points in the inequalities and see what works. Here, we evaluate the point in the first inequality, and if that works, then the second inequality.
A. 2 ≤ -(-5) -5 . . . ⇒ . . . 2 ≤ 0 . . . false
B. -2 ≤ 5 -5 . . . true
... -2 ≥ -(5) -4 . . . true . . . . . . selection B is a viable choice
C. we know from A that the first inequality will be satisfied
... -2 ≥ -(-5) -4 . . . ⇒ . . . -2 ≥ 1 . . . false
D. 2 ≤ 5 -5 . . . . false
Answer:
a = 24*1/3
a =8
Step-by-step explanation:
We are using proportions to solve this problem by putting students over adults
students 3 24
--------------- = --------------- = -------------
adults 1 a
where a is the unknown number of adults
Using cross products
3a=24*1
Divide by 3
a = 24*1/3
a = 24/3
a = 8
Let u = x², then we would have u² + 5u - 6 = 0
From here, we can factor it and get us (u-1)(u+6) = 0
So our solution for u is u = -6 or 1.
Now substitute u back to x².
x² = -6 or 1
x = ±√(-6) or ±√1
Since ±√(-6) is not real number, we ignore it.
Which leave us x = ±√1 = <span>±1
So our real solution is x = -1 or 1.</span>
Answer:
x=10
Step-by-step explanation:
hope it helps
