She spent 35 minutes doing her homework
Answer:
there is two terms. 3x^4 and 2y)^7
please mark as brainliest
First one;
As it factorises to:
f(x) = (x - 7)(x + 4)
Which, if set equal to 0, will solve to give the desired solutions like so:
f(x) = (x - 7)(x + 4) = 0
x - 7 = 0 x + 4 = 0
x = 7 x = -4
None of the other quadratics solve to give desired solutions when set equal to 0.
The answer is 41
Step-by-step explanation:
To solve this we must use the formula a^2+b^2=c^2. if we substitute in the values we get 9^2+40^2=c^2. The first variable is 81, then the b variable is 1600. The hypotenuse is the c value. 81+1600 is 1681, now we must find the square root of 1681. The answer is 41. Tell me if I'm wrong :)
The statement <span>The coefficient of x^k y^n-k in the expansion of (x+y)^n equals (n-k / k) is true. This will show the standard formula and the expansion of it. We all know that it can still be expanded based on the power or degree of the terms.</span>