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lora16 [44]
3 years ago
9

Solve the triangle. a = 10, b = 23, C = 95° (2 points) c ≈ 25.1, A ≈ 26.8°, B ≈ 58.2° c ≈ 25.1, A ≈ 22.8°, B ≈ 62.2° c ≈ 25.9, A

≈ 22.8°, B ≈ 62.2° c ≈ 25.9, A ≈ 59.2°, B ≈ 25.8°

Mathematics
1 answer:
lara31 [8.8K]3 years ago
5 0

Answer:

c ≈ 25.9, A ≈ 22.8°, B ≈ 62.2°

Step-by-step explanation:

The Law of Cosines can be used to find the third side.

... c² = a² + b² - 2ab·cos(C)

... c² ≈ 100 +529 -2·10·23·cos(95°)

... c² ≈ 669.0916

... c ≈ √669.0916 ≈ 25.87

From the Law of Sines, we can find the remaining angles.

... sin(B)/b = sin(C)/c

... B = arcsin(b/c·sin(C)) ≈ 62.35°

These results are sufficient to make the appropriate answer choice.

_____

<em>Comment on Answer Discrepancies</em>

If the "c" used in the calculation of B is inappropriately rounded to 25.9, then the result for angle B is 62.21°. This is in error by more than 0.1°. Intermediate results should <em>never</em> be rounded, but should be carried to full calculator precision. Only final answers should be rounded.

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What is the probability that a junior non-Nutrition major and then a sophomore Nutrition major are chosen at random? Express you
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Answer:

0.0032

The complete question as seen in other website:

There are 111 students in a nutrition class. The instructor must choose two students at random Students in a Nutrition Class Nutrition majors Academic Year Freshmen non-Nutrition majors 17 18 Sophomores Juniors 13 Seniors 18 Copy Data. What is the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.

Step-by-step explanation:

Total number of in a nutrition class = 111 students

To determine the probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major, we would find the probability of each of them.

Let the probability of choosing a junior non-Nutrition major = Pr (j non-N)

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= 39/12321

= 0.0032

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4 years ago
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